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Slack isn’t even the word it’s more &#108&#105&#107&#101 &#102&#97&#105&#108&#101&#100&#46 &#73&#116 &#97&#108&#109&#111&#115&#116 &#108&#105&#116&#101&#114&#97&#108&#108&#121 had zero resin. Because the other 2 were nice plants this one was given a second chance before meeting its maker. Make the grade when grown from clone it didn't.<br> Meet its maker it did, good riddance. Aroma: These babies &#115&#116&#105&#110&#107&#46 &#84&#104&#101&#121 &#115&#109&#101&#108&#108 &#119&#104&#101&#110 they’re young seedlings, vegging, rooting and flowering. The smell from just 2 vegging plants, 1 &#97&#110&#100 &#50 &#99&#97&#117&#115&#101&#100 &#109&#111&#114&#101 noticeable &#111&#100&#111&#114 &#116&#104&#97&#110 &#104&#97&#108&#102 &#116&#104&#101 same grow filled &#119&#105&#116&#104&#13&#10&#102&#108&#111&#119&#101&#114&#105&#110&#103 &#78&#76 &#120 &#83&#104&#105&#118&#97&#39&#115&#46 &#13&#10&#78&#111&#46 They didn’t &#115&#109&#101&#108&#108 &#108&#105&#107&#101 &#98&#108&#117&#101&#98&#101&#114&#114&#105&#101&#115 &#116&#111 me but &#100&#105&#100 &#104&#97&#118&#101 &#115&#111&#109&#101&#116&#104&#105&#110&#103 &#97&#100&#100&#101&#100 to the sweet &#115&#107&#117&#110&#107&#121 &#105&#110&#100&#105&#99&#97 &#111&#100&#111&#114&#13&#10&#116&#104&#97&#116 &#104&#97&#115 a berry quality to it. It is becoming &#115&#116&#105&#110&#107&#105&#101&#114 &#97&#115 &#105&#116 &#97&#103&#101&#115 too. For those of you that have &#102&#114&#105&#101&#110&#100&#115 &#116&#104&#97&#116 &#97&#114&#101&#13&#10&#105&#109&#112&#114&#101&#115&#115&#101&#100 &#119&#105&#116&#104 smell &#116&#104&#105&#115 &#119&#111&#117&#108&#100 &#98&#101 &#97 winner. Max security &#99&#97&#108&#108&#115 &#102&#111&#114 &#112&#97&#121&#105&#110&#103 &#98&#105&#103 time &#97&#116&#116&#101&#110&#116&#105&#111&#110 &#116&#111 &#111&#100&#111&#114 &#99&#111&#110&#116&#114&#111&#108 in the grow with these. Except of course for 3 which doesn’t smell like anything but the lawn. This weed would present a packaging &#99&#104&#97&#108&#108&#101&#110&#103&#101 &#105&#102 &#121&#111&#117 &#110&#101&#101&#100 to move it for some unknown reason - Buzz: As &#115&#116&#97&#116&#101&#100 &#116&#104&#101 &#116&#119&#111 &#114&#101&#109&#97&#105&#110&#105&#110&#103 plants had better than average potency for this age. Both were <a href="http://cannabica.net/markemeryseeds com.shtml" title="Markemeryseeds Com" alt="Markemeryseeds Com" >Markemeryseeds Com</a> definitely indica types &#98&#117&#122&#122&#105&#110&#103 &#119&#105&#116&#104 &#50 &#98&#101&#105&#110&#103 somewhat unique with &#97 &#104&#101&#97&#100&#121 <a href="http://cannabica.net/growing marijuana seeds/" title="Marijuana Seeds Growing" alt="Marijuana Seeds Growing" >Marijuana Seeds Growing</a> &#102&#108&#111&#97&#116&#121 &#116&#121&#112&#101 thing going on. More later when they’re older but I will say &#116&#104&#101 &#98&#117&#122&#122 &#104&#97&#115 &#115&#111&#109&#101 unique qualities &#99&#111&#109&#112&#97&#114&#101&#100 &#116&#111 &#101&#118&#101&#114&#121&#116&#104&#105&#110&#103 &#101&#108&#115&#101 worth keeping more than likely.<br> <a href="http://cannabica.net/seed banks.shtml" title="Seed Banks" alt="Seed Banks" >Seed Banks</a></p> <h2> shishkaberry seeds for sale</h2> <p><p align="left"> which there is no change in the gene &#112&#111&#111&#108&#46 &#84&#104&#105&#115 &#109&#101&#97&#110&#115 &#116&#104&#97&#116&#13&#10&#116&#104&#101&#114&#101 &#99&#97&#110 be no evolution. For a test &#101&#120&#97&#109&#112&#108&#101 &#108&#101&#116 &#117&#115 &#99&#111&#110&#115&#105&#100&#101&#114 a &#112&#111&#112&#117&#108&#97&#116&#105&#111&#110 &#119&#104&#111&#115&#101 &#103&#101&#110&#101&#13&#10&#112&#111&#111&#108 &#99&#111&#110&#116&#97&#105&#110&#115 the alleles B and &#98&#46 &#65&#115&#115&#105&#103&#110 &#116&#104&#101 &#108&#101&#116&#116&#101&#114 c to the frequency of the dominant allele &#66 &#97&#110&#100 &#116&#104&#101 &#108&#101&#116&#116&#101&#114 d to the frequency of &#116&#104&#101&#13&#10&#114&#101&#99&#101&#115&#115&#105&#118&#101 &#97&#108&#108&#101&#108&#101 &#98&#46&#13&#10&#91&#73&#110 &#109&#111&#115&#116 cases you will find that c and &#100 &#97&#114&#101 &#97&#99&#116&#117&#97&#108&#108&#121 &#110&#111&#116&#97&#116&#101&#100&#13&#10&#97&#115 p and q by convention in science, but for this example we will use c and d.] The sum of all the alleles &#109&#117&#115&#116 &#101&#113&#117&#97&#108 &#49&#48&#48&#37&#46&#13&#10&#83&#111 &#99 &#43 d = 1. All the random &#112&#111&#115&#115&#105&#98&#108&#101 &#99&#111&#109&#98&#105&#110&#97&#116&#105&#111&#110&#115 &#111&#102 &#116&#104&#101 &#109&#101&#109&#98&#101&#114&#115 of &#97&#13&#10&#112&#111&#112&#117&#108&#97&#116&#105&#111&#110 &#119&#111&#117&#108&#100 &#101&#113&#117&#97&#108 &#40&#99 x c) + 2cd + (d x d). Which can &#97&#108&#115&#111 &#98&#101&#13&#10&#101&#120&#112&#114&#101&#115&#115&#101&#100 &#97&#115&#58&#13&#10&#40&#99&#43&#100&#41 &#88 (c+d) We will explain this &#105&#110 &#100&#101&#116&#97&#105&#108 &#105&#110 &#109&#111&#109&#101&#110&#116&#44 &#98&#117&#116 it is best to know it for now.<br> The frequencies of B and b will remain unchanged generation after generation if: 1. The population is large enough.<br> 2.<br> &#84&#104&#101&#114&#101 &#97&#114&#101 &#110&#111 &#109&#117&#116&#97&#116&#105&#111&#110&#115&#46&#13&#10&#50&#57&#53&#13&#10&#51&#46 There are no preferences. For example a BB male does &#110&#111&#116 &#112&#114&#101&#102&#101&#114 &#97&#13&#10&#98&#98 &#102&#101&#109&#97&#108&#101 by its nature.<br> 4.<br> No other outside population exchanges genes with this model. 5. Natural selection must not favor any specific individual. Let us imagine a pool of genes. 12 are B and 18 are &#98&#46 &#78&#111&#119&#13&#10&#114&#101&#109&#101&#109&#98&#101&#114 &#84&#104&#101 &#115&#117&#109 of all the alleles must equal 100%. So this means that the total in this case is &#49&#50 &#43 &#49&#56 &#61 &#51&#48&#46 So 30 is &#49&#48&#48&#37&#46&#13&#10&#73&#102 &#119&#101 &#119&#97&#110&#116 &#116&#111 find the frequencies of B and b and the genotypic frequencies of B, Bb and &#98 &#116&#104&#101&#110 &#119&#101 &#119&#105&#108&#108 have to apply the standard formula that we have just been shown.<br> f (B) = 12/30 = &#48&#46&#52 &#61 &#52&#48&#37&#13&#10&#102 &#40&#98&#41 = 18/30 &#61 &#48&#46&#54 &#61 &#54&#48&#37&#13&#10&#66&#111&#116&#104 add to &#109&#97&#107&#101 &#49&#48&#48&#37&#46 &#78&#111&#119 &#119&#101 know their &#114&#97&#116&#105&#111&#115&#46&#13&#10&#83&#111&#44&#13&#10&#99 &#43 &#100 &#61 &#48&#46&#52 + 0.6 = &#49&#13&#10&#87&#101 &#104&#97&#118&#101 &#112&#114&#111&#118&#101&#110 &#116&#104&#97&#116 c &#43 &#100 &#109&#117&#115&#116 &#101&#113&#117&#97&#108 &#49&#46&#13&#10&#86&#101&#114&#121 straightforward, yes.<br> 296 Remember that all the random possible combinations of the members of &#97 &#112&#111&#112&#117&#108&#97&#116&#105&#111&#110 &#119&#111&#117&#108&#100 &#101&#113&#117&#97&#108 (c x c) + 2cd + (d x d), or &#40&#99&#43&#100&#41 &#88 &#40&#99&#43&#100&#41&#13&#10&#84&#104&#101&#110&#44 &#99 + d &#61 &#48&#46&#52 &#43 &#48&#46&#54 = 1 And (c x c) + 2cd &#43 &#40&#100 &#120 &#100&#41&#13&#10&#61 BB + &#66&#98 &#43 &#98&#98&#13&#10&#61 &#46&#50&#52 + .48 + .30 = 1 This means that the population can increase in size, but the frequencies of B and b &#119&#105&#108&#108 &#115&#116&#97&#121 &#116&#104&#101 &#115&#97&#109&#101&#46&#13&#10&#78&#111&#119&#44 suppose we break the 4th &#108&#97&#119 &#97&#98&#111&#117&#116 &#110&#111&#116 &#105&#110&#116&#114&#111&#100&#117&#99&#105&#110&#103 another population into this one.<br> Let us say that we add 4 more b. b + b + b + b enter the pool. This brings our total up to &#51&#52 &#105&#110&#115&#116&#101&#97&#100 &#111&#102&#13&#10&#51&#48&#46 &#87&#104&#97&#116 &#119&#105&#108&#108 the gene and genotypic frequencies be? f (B) = 12/34 = .35 = 35 % f (b) &#61 &#50&#50&#47&#51&#52 &#61 &#46&#54&#53 = 65% f (BB) = .12, f (Bb) = .23 and f (bb) = .42 Oppss, .42 does not equal 1. This means that &#116&#104&#101 &#69&#113&#117&#105&#108&#105&#98&#114&#105&#117&#109 &#108&#97&#119 &#102&#97&#105&#108&#115&#13&#10&#105&#102 &#116&#104&#101 4th law is not met. &#87&#104&#101&#110 &#116&#104&#101 &#110&#101&#119 &#103&#101&#110&#101&#115 entered the pool it resulted &#105&#110 &#97 &#99&#104&#97&#110&#103&#101 &#111&#102 the population’s gene frequencies.<br> However &#105&#102&#13&#10&#50&#57&#55&#13&#10&#110&#111 &#111&#116&#104&#101&#114 &#112&#111&#112&#117&#108&#97&#116&#105&#111&#110&#115 &#119&#104&#101&#114&#101 &#105&#110&#116&#114&#111&#100&#117&#99&#101&#100 then &#116&#104&#101 &#102&#114&#101&#113&#117&#101&#110&#99&#121 &#111&#102 &#46&#52&#50 would be maintained generation after generation. However we would like &#116&#111 &#112&#111&#105&#110&#116 &#111&#117&#116 &#116&#104&#97&#116 we used a very &#115&#109&#97&#108&#108&#13&#10&#112&#111&#111&#108 &#105&#110 &#116&#104&#101 &#97&#98&#111&#118&#101 example. If the pool were much &#108&#97&#114&#103&#101&#114 &#116&#104&#101&#110 &#116&#104&#101&#13&#10&#110&#117&#109&#98&#101&#114 &#111&#102 changes, even if one or &#116&#119&#111 &#110&#101&#119 &#103&#101&#110&#101&#115 &#106&#117&#109&#112&#101&#100 &#105&#110&#44 would be insignificant.<br> You could calculate &#105&#116&#44 &#98&#117&#116 &#116&#104&#101 &#99&#104&#97&#110&#103&#101 would be on an extremely low levewhich &#116&#104&#101&#114&#101 &#105&#115 &#110&#111 &#99&#104&#97&#110&#103&#101 in the &#103&#101&#110&#101 &#112&#111&#111&#108&#46 &#84&#104&#105&#115 &#109&#101&#97&#110&#115 that there can be no evolution.<br> For a test example let us consider a population whose gene pool &#99&#111&#110&#116&#97&#105&#110&#115 &#116&#104&#101 &#97&#108&#108&#101&#108&#101&#115 &#66 and b. Assign the letter c to &#116&#104&#101 &#102&#114&#101&#113&#117&#101&#110&#99&#121&#13&#10&#111&#102 &#116&#104&#101 &#100&#111&#109&#105&#110&#97&#110&#116 allele B and &#116&#104&#101 &#108&#101&#116&#116&#101&#114 &#100 &#116&#111 the frequency of the recessive allele b.<br> In most cases you &#119&#105&#108&#108 &#102&#105&#110&#100 &#116&#104&#97&#116 &#99 and d are actually notated as p and q &#98&#121 &#99&#111&#110&#118&#101&#110&#116&#105&#111&#110 &#105&#110 &#115&#99&#105&#101&#110&#99&#101&#44 but for this example we will &#117&#115&#101 &#99&#13&#10&#97&#110&#100 &#100&#46&#93&#13&#10&#84&#104&#101 &#115&#117&#109 of all &#116&#104&#101 &#97&#108&#108&#101&#108&#101&#115 &#109&#117&#115&#116 &#101&#113&#117&#97&#108 100%. So c + &#100 &#61 &#49&#46&#13&#10&#65&#108&#108 &#116&#104&#101 random possible combinations of &#116&#104&#101 &#109&#101&#109&#98&#101&#114&#115 &#111&#102 &#97&#13&#10&#112&#111&#112&#117&#108&#97&#116&#105&#111&#110 would equal (c x c) + &#50&#99&#100 &#43 &#40&#100 &#120 d). Which can also &#98&#101&#13&#10&#101&#120&#112&#114&#101&#115&#115&#101&#100 &#97&#115&#58&#13&#10&#40&#99&#43&#100&#41 &#88 &#40&#99&#43&#100&#41&#13&#10&#87&#101 will explain this in detail in moment, but it is best &#116&#111 &#107&#110&#111&#119 &#105&#116 &#102&#111&#114&#13&#10&#110&#111&#119&#46&#13&#10&#84&#104&#101 &#102&#114&#101&#113&#117&#101&#110&#99&#105&#101&#115 of B and &#98 &#119&#105&#108&#108 &#114&#101&#109&#97&#105&#110 &#117&#110&#99&#104&#97&#110&#103&#101&#100 generation after generation if: 1. &#84&#104&#101 &#112&#111&#112&#117&#108&#97&#116&#105&#111&#110 &#105&#115 &#108&#97&#114&#103&#101 enough. 2. &#84&#104&#101&#114&#101 &#97&#114&#101 &#110&#111 &#109&#117&#116&#97&#116&#105&#111&#110&#115&#46&#13&#10&#50&#57&#53&#13&#10&#51&#46 There &#97&#114&#101 &#110&#111 &#112&#114&#101&#102&#101&#114&#101&#110&#99&#101&#115&#46 &#70&#111&#114 example a BB male does not prefer a bb female by &#105&#116&#115 &#110&#97&#116&#117&#114&#101&#46&#13&#10&#52&#46 &#78&#111 &#111&#116&#104&#101&#114 &#111&#117&#116&#115&#105&#100&#101 population exchanges genes with this model. 5. Natural selection must not &#102&#97&#118&#111&#114 &#97&#110&#121 &#115&#112&#101&#99&#105&#102&#105&#99 &#105&#110&#100&#105&#118&#105&#100&#117&#97&#108&#46&#13&#10&#76&#101&#116 us &#105&#109&#97&#103&#105&#110&#101 &#97 &#112&#111&#111&#108 &#111&#102 genes.<br> 12 are B &#97&#110&#100 &#49&#56 &#97&#114&#101 &#98&#46 Now remember The sum of all the &#97&#108&#108&#101&#108&#101&#115 &#109&#117&#115&#116 &#101&#113&#117&#97&#108 &#49&#48&#48&#37&#46 So this &#109&#101&#97&#110&#115&#13&#10&#116&#104&#97&#116 &#116&#104&#101 &#116&#111&#116&#97&#108 &#105&#110 this case is &#49&#50 &#43 &#49&#56 &#61 30. So &#51&#48 &#105&#115 &#49&#48&#48&#37&#46&#13&#10&#73&#102 &#119&#101 want to find &#116&#104&#101 &#102&#114&#101&#113&#117&#101&#110&#99&#105&#101&#115 &#111&#102 &#66 &#97&#110&#100 &#98 and the genotypic frequencies of B, Bb and b then we will have to apply the standard formula that &#119&#101 &#104&#97&#118&#101 &#106&#117&#115&#116 &#98&#101&#101&#110 shown.<br> f (B) = 12/30 = 0.4 = 40% f (b) = 18/30 = 0.6 = 60% Both add to make 100%. Now &#119&#101 &#107&#110&#111&#119 &#116&#104&#101&#105&#114 &#114&#97&#116&#105&#111&#115&#46&#13&#10&#83&#111&#44&#13&#10&#99 + &#100 &#61 &#48&#46&#52 &#43 0.6 = 1 We have proven that &#99 &#43 &#100 &#109&#117&#115&#116 equal 1. Very straightforward, yes. 296 Remember that all the random possible combinations of the members of a population &#119&#111&#117&#108&#100 &#101&#113&#117&#97&#108 &#40&#99 &#120 c) + 2cd + (d x d), or (c+d) X &#40&#99&#43&#100&#41&#13&#10&#84&#104&#101&#110&#44 &#99 &#43 &#100 = &#48&#46&#52 &#43 &#48&#46&#54 &#61 1 And (c x &#99&#41 &#43 &#50&#99&#100 &#43 (d x &#100&#41&#13&#10&#61 &#66&#66 &#43 &#66&#98 + bb = .24 + .48 + &#46&#51&#48 &#61 &#49&#13&#10&#84&#104&#105&#115 &#109&#101&#97&#110&#115 &#116&#104&#97&#116 the population can &#105&#110&#99&#114&#101&#97&#115&#101 &#105&#110 &#115&#105&#122&#101&#44 &#98&#117&#116 &#116&#104&#101&#13&#10&#102&#114&#101&#113&#117&#101&#110&#99&#105&#101&#115 of B and b will stay the same. Now, suppose we break the 4th law about &#110&#111&#116 &#105&#110&#116&#114&#111&#100&#117&#99&#105&#110&#103 &#97&#110&#111&#116&#104&#101&#114&#13&#10&#112&#111&#112&#117&#108&#97&#116&#105&#111&#110 &#105&#110&#116&#111 this one. Let us &#115&#97&#121 &#116&#104&#97&#116 &#119&#101 &#97&#100&#100 4 more b. b + b + b + b enter the pool. &#84&#104&#105&#115 &#98&#114&#105&#110&#103&#115 &#111&#117&#114 &#116&#111&#116&#97&#108 up to &#51&#52 &#105&#110&#115&#116&#101&#97&#100 &#111&#102&#13&#10&#51&#48&#46 &#87&#104&#97&#116 &#119&#105&#108&#108 the &#103&#101&#110&#101 &#97&#110&#100 &#103&#101&#110&#111&#116&#121&#112&#105&#99 &#102&#114&#101&#113&#117&#101&#110&#99&#105&#101&#115 be? f (B) = 12/34 = &#46&#51&#53 &#61 &#51&#53 &#37&#13&#10&#102 &#40&#98&#41 = 22/34 = &#46&#54&#53 &#61 &#54&#53&#37&#13&#10&#102 &#40&#66&#66&#41 = .12, f (Bb) = .23 and &#102 &#40&#98&#98&#41 &#61 &#46&#52&#50&#13&#10&#79&#112&#112&#115&#115&#44 .42 &#100&#111&#101&#115 &#110&#111&#116 &#101&#113&#117&#97&#108 &#49&#46 &#84&#104&#105&#115 means that the Equilibrium law &#102&#97&#105&#108&#115&#13&#10&#105&#102 &#116&#104&#101 &#52&#116&#104 &#108&#97&#119 is not &#109&#101&#116&#46 &#87&#104&#101&#110 &#116&#104&#101 &#110&#101&#119 genes entered the &#112&#111&#111&#108 &#105&#116&#13&#10&#114&#101&#115&#117&#108&#116&#101&#100 &#105&#110 &#97 change of the &#112&#111&#112&#117&#108&#97&#116&#105&#111&#110&#8217&#115 &#103&#101&#110&#101 &#102&#114&#101&#113&#117&#101&#110&#99&#105&#101&#115&#46 &#72&#111&#119&#101&#118&#101&#114 if 297 no other &#112&#111&#112&#117&#108&#97&#116&#105&#111&#110&#115 &#119&#104&#101&#114&#101 &#105&#110&#116&#114&#111&#100&#117&#99&#101&#100 &#116&#104&#101&#110 the frequency of .42 would be maintained generation &#97&#102&#116&#101&#114 &#103&#101&#110&#101&#114&#97&#116&#105&#111&#110&#46&#13&#10&#72&#111&#119&#101&#118&#101&#114 &#119&#101 &#119&#111&#117&#108&#100 like to point out that &#119&#101 &#117&#115&#101&#100 &#97 &#118&#101&#114&#121 &#115&#109&#97&#108&#108&#13&#10&#112&#111&#111&#108 &#105&#110 the above example. If the pool were much larger then the number of changes, even &#105&#102 &#111&#110&#101 &#111&#114 &#116&#119&#111 new genes jumped &#105&#110&#44 &#119&#111&#117&#108&#100 &#98&#101&#13&#10&#105&#110&#115&#105&#103&#110&#105&#102&#105&#99&#97&#110&#116&#46 &#89&#111&#117 could calculate &#105&#116&#44 &#98&#117&#116 &#116&#104&#101 &#99&#104&#97&#110&#103&#101 &#119&#111&#117&#108&#100 be on an extremely low levewhich &#116&#104&#101&#114&#101 &#105&#115 &#110&#111 &#99&#104&#97&#110&#103&#101 in the gene pool. This means &#116&#104&#97&#116&#13&#10&#116&#104&#101&#114&#101 &#99&#97&#110 &#98&#101 &#110&#111 evolution. For &#97 &#116&#101&#115&#116 &#101&#120&#97&#109&#112&#108&#101 &#108&#101&#116 &#117&#115 consider a &#112&#111&#112&#117&#108&#97&#116&#105&#111&#110 &#119&#104&#111&#115&#101 &#103&#101&#110&#101&#13&#10&#112&#111&#111&#108 &#99&#111&#110&#116&#97&#105&#110&#115 the alleles B and b. Assign the letter c to &#116&#104&#101 &#102&#114&#101&#113&#117&#101&#110&#99&#121&#13&#10&#111&#102 &#116&#104&#101 &#100&#111&#109&#105&#110&#97&#110&#116 allele B and the &#108&#101&#116&#116&#101&#114 &#100 &#116&#111 &#116&#104&#101 frequency of the recessive allele b. In most cases you &#119&#105&#108&#108 &#102&#105&#110&#100 &#116&#104&#97&#116 &#99 and d are &#97&#99&#116&#117&#97&#108&#108&#121 &#110&#111&#116&#97&#116&#101&#100&#13&#10&#97&#115 &#112 &#97&#110&#100 &#113 by convention in science, but for this example we will &#117&#115&#101 &#99&#13&#10&#97&#110&#100 &#100&#46&#13&#10&#84&#104&#101 &#115&#117&#109 of all the alleles <a href="http://cannabica.net/sprout marijuana seeds.shtml" title="Sprout seeds Sprout seeds Sprout" alt="Sprout seeds Sprout seeds Sprout" >Sprout seeds Sprout seeds Sprout</a> must equal &#49&#48&#48&#37&#46&#13&#10&#83&#111 &#99 &#43 &#100 = 1.<br> All the random possible combinations of the &#109&#101&#109&#98&#101&#114&#115 &#111&#102 &#97&#13&#10&#112&#111&#112&#117&#108&#97&#116&#105&#111&#110 &#119&#111&#117&#108&#100 &#101&#113&#117&#97&#108 (c x c) + 2cd + (d x d). Which can &#97&#108&#115&#111 &#98&#101&#13&#10&#101&#120&#112&#114&#101&#115&#115&#101&#100 &#97&#115&#58&#13&#10&#40&#99&#43&#100&#41 &#88 (c+d) We will &#101&#120&#112&#108&#97&#105&#110 &#116&#104&#105&#115 &#105&#110 &#100&#101&#116&#97&#105&#108 in moment, but it is best to know it for now. The frequencies of B and b &#119&#105&#108&#108 &#114&#101&#109&#97&#105&#110 &#117&#110&#99&#104&#97&#110&#103&#101&#100 &#103&#101&#110&#101&#114&#97&#116&#105&#111&#110 after generation if: 1. The population is large enough. 2. There &#97&#114&#101 &#110&#111 &#109&#117&#116&#97&#116&#105&#111&#110&#115&#46&#13&#10&#50&#57&#53&#13&#10&#51&#46 &#84&#104&#101&#114&#101 &#97&#114&#101 no preferences. For example a BB &#109&#97&#108&#101 &#100&#111&#101&#115 &#110&#111&#116 &#112&#114&#101&#102&#101&#114 a bb female by its nature. 4. No other outside &#112&#111&#112&#117&#108&#97&#116&#105&#111&#110 &#101&#120&#99&#104&#97&#110&#103&#101&#115 &#103&#101&#110&#101&#115 &#119&#105&#116&#104 this model. 5. Natural &#115&#101&#108&#101&#99&#116&#105&#111&#110 &#109&#117&#115&#116 &#110&#111&#116 &#102&#97&#118&#111&#114 any &#115&#112&#101&#99&#105&#102&#105&#99 &#105&#110&#100&#105&#118&#105&#100&#117&#97&#108&#46&#13&#10&#76&#101&#116 &#117&#115 &#105&#109&#97&#103&#105&#110&#101 &#97 pool &#111&#102 &#103&#101&#110&#101&#115&#46 &#49&#50 &#97&#114&#101 B and 18 are b. &#78&#111&#119&#13&#10&#114&#101&#109&#101&#109&#98&#101&#114 &#84&#104&#101 &#115&#117&#109 &#111&#102 all the alleles &#109&#117&#115&#116 &#101&#113&#117&#97&#108 &#49&#48&#48&#37&#46 &#83&#111 this means that the total in this case &#105&#115 &#49&#50 &#43 &#49&#56 &#61 30. So 30 is &#49&#48&#48&#37&#46&#13&#10&#73&#102 &#119&#101 &#119&#97&#110&#116 &#116&#111 find &#116&#104&#101 &#102&#114&#101&#113&#117&#101&#110&#99&#105&#101&#115 &#111&#102 &#66 and b and the genotypic frequencies of B, &#66&#98 &#97&#110&#100 &#98 &#116&#104&#101&#110 &#119&#101 will have to apply the standard &#102&#111&#114&#109&#117&#108&#97 &#116&#104&#97&#116 &#119&#101 &#104&#97&#118&#101 just been shown. f (B) = &#49&#50&#47&#51&#48 &#61 &#48&#46&#52 &#61 40% f (b) = 18/30 = &#48&#46&#54 &#61 &#54&#48&#37&#13&#10&#66&#111&#116&#104 &#97&#100&#100 to make &#49&#48&#48&#37&#46 &#78&#111&#119 &#119&#101 &#107&#110&#111&#119 their ratios.<br> So, c &#43 &#100 &#61 &#48&#46&#52 &#43 0.6 &#61 &#49&#13&#10&#87&#101 &#104&#97&#118&#101 &#112&#114&#111&#118&#101&#110 that c + d must equal 1. Very straightforward, &#121&#101&#115&#46&#13&#10&#50&#57&#54&#13&#10&#82&#101&#109&#101&#109&#98&#101&#114 &#116&#104&#97&#116 &#97&#108&#108 &#116&#104&#101 &#114&#97&#110&#100&#111&#109 &#112&#111&#115&#115&#105&#98&#108&#101 combinations of the members of a population would equal (c &#120 &#99&#41 &#43 &#50&#99&#100 + (d &#120 &#100&#41&#44 &#111&#114 &#40&#99&#43&#100&#41 X &#40&#99&#43&#100&#41&#13&#10&#84&#104&#101&#110&#44 &#99 &#43 &#100 = 0.4 &#43 &#48&#46&#54 &#61 &#49&#13&#10&#65&#110&#100 (c x c) + 2cd + (d x d) = BB + Bb + bb = .24 + .48 + &#46&#51&#48 &#61 &#49&#13&#10&#84&#104&#105&#115 &#109&#101&#97&#110&#115 that the population can increase in size, &#98&#117&#116 &#116&#104&#101&#13&#10&#102&#114&#101&#113&#117&#101&#110&#99&#105&#101&#115 &#111&#102 &#66 and b will stay the same. Now, suppose we break the 4th law about not introducing another population into &#116&#104&#105&#115 &#111&#110&#101&#46&#13&#10&#76&#101&#116 &#117&#115 &#115&#97&#121 that we add 4 more b. b + b + b + b &#101&#110&#116&#101&#114 &#116&#104&#101 &#112&#111&#111&#108&#46 &#84&#104&#105&#115 &#98&#114&#105&#110&#103&#115 our &#116&#111&#116&#97&#108 &#117&#112 &#116&#111 &#51&#52 instead of 30. What will the gene and genotypic &#102&#114&#101&#113&#117&#101&#110&#99&#105&#101&#115 &#98&#101&#63&#13&#10&#102 &#40&#66&#41 &#61 &#49&#50&#47&#51&#52 = .35 = 35 % f (b) = 22/34 = .65 = 65% f (BB) &#61 &#46&#49&#50&#44 &#102 &#40&#66&#98&#41 = .23 and f (bb) = .42 Oppss, .42 does not equal 1. This means that the &#69&#113&#117&#105&#108&#105&#98&#114&#105&#117&#109 &#108&#97&#119 &#102&#97&#105&#108&#115&#13&#10&#105&#102 &#116&#104&#101 4th law is not met. When &#116&#104&#101 &#110&#101&#119 &#103&#101&#110&#101&#115 &#101&#110&#116&#101&#114&#101&#100 the &#112&#111&#111&#108 &#105&#116&#13&#10&#114&#101&#115&#117&#108&#116&#101&#100 &#105&#110 &#97 change of the population’s gene frequencies. However &#105&#102&#13&#10&#50&#57&#55&#13&#10&#110&#111 &#111&#116&#104&#101&#114 &#112&#111&#112&#117&#108&#97&#116&#105&#111&#110&#115 &#119&#104&#101&#114&#101 introduced then the frequency &#111&#102 &#46&#52&#50 &#119&#111&#117&#108&#100&#13&#10&#98&#101 &#109&#97&#105&#110&#116&#97&#105&#110&#101&#100 generation &#97&#102&#116&#101&#114 &#103&#101&#110&#101&#114&#97&#116&#105&#111&#110&#46&#13&#10&#72&#111&#119&#101&#118&#101&#114 &#119&#101 &#119&#111&#117&#108&#100 like to point out that &#119&#101 &#117&#115&#101&#100 &#97 &#118&#101&#114&#121 &#115&#109&#97&#108&#108&#13&#10&#112&#111&#111&#108 &#105&#110 the above example. If the &#112&#111&#111&#108 &#119&#101&#114&#101 &#109&#117&#99&#104 &#108&#97&#114&#103&#101&#114 then the number &#111&#102 &#99&#104&#97&#110&#103&#101&#115&#44 &#101&#118&#101&#110 &#105&#102 one or &#116&#119&#111 &#110&#101&#119 &#103&#101&#110&#101&#115 &#106&#117&#109&#112&#101&#100 in, would be insignificant. You could calculate it, &#98&#117&#116 &#116&#104&#101 &#99&#104&#97&#110&#103&#101 &#119&#111&#117&#108&#100 be on an extremely low levewhich there is no change &#105&#110 &#116&#104&#101 &#103&#101&#110&#101 &#112&#111&#111&#108&#46 This means that there can be no evolution.<br> For a test example &#108&#101&#116 &#117&#115 &#99&#111&#110&#115&#105&#100&#101&#114 &#97 population whose &#103&#101&#110&#101&#13&#10&#112&#111&#111&#108 &#99&#111&#110&#116&#97&#105&#110&#115 &#116&#104&#101 &#97&#108&#108&#101&#108&#101&#115 B and b. Assign the letter c to the frequency of the dominant &#97&#108&#108&#101&#108&#101 &#66 &#97&#110&#100 &#116&#104&#101 letter d to the frequency of the recessive allele b. In most cases you will find that c &#97&#110&#100 &#100 &#97&#114&#101 &#97&#99&#116&#117&#97&#108&#108&#121 &#110&#111&#116&#97&#116&#101&#100&#13&#10&#97&#115 p and &#113 &#98&#121 &#99&#111&#110&#118&#101&#110&#116&#105&#111&#110 &#105&#110 science, but for &#116&#104&#105&#115 &#101&#120&#97&#109&#112&#108&#101 &#119&#101 &#119&#105&#108&#108 use c and d.<br> The sum &#111&#102 &#97&#108&#108 &#116&#104&#101 &#97&#108&#108&#101&#108&#101&#115 &#109&#117&#115&#116 &#101&#113&#117&#97&#108 100%.<br> So c + d &#61 &#49&#46&#13&#10&#65&#108&#108 &#116&#104&#101 &#114&#97&#110&#100&#111&#109 &#112&#111&#115&#115&#105&#98&#108&#101 combinations of the members of a population would equal (c x &#99&#41 &#43 &#50&#99&#100 &#43 (d &#120 &#100&#41&#46 &#87&#104&#105&#99&#104 &#99&#97&#110 &#97&#108&#115&#111 be expressed as: (c+d) X (c+d) We will explain this in detail in moment, but it is best to know it for now. The frequencies of B and b &#119&#105&#108&#108 &#114&#101&#109&#97&#105&#110 &#117&#110&#99&#104&#97&#110&#103&#101&#100 &#103&#101&#110&#101&#114&#97&#116&#105&#111&#110 after generation if: 1. The population &#105&#115 &#108&#97&#114&#103&#101 &#101&#110&#111&#117&#103&#104&#46&#13&#10&#50&#46 &#84&#104&#101&#114&#101 are no mutations.<br> 295 3.<br> There are no preferences.<br> For example a &#66&#66 &#109&#97&#108&#101 &#100&#111&#101&#115 &#110&#111&#116 prefer a bb female by its nature. 4. &#78&#111 &#111&#116&#104&#101&#114 &#111&#117&#116&#115&#105&#100&#101 &#112&#111&#112&#117&#108&#97&#116&#105&#111&#110 &#101&#120&#99&#104&#97&#110&#103&#101&#115 genes with this model. 5. Natural selection must not favor any specific &#105&#110&#100&#105&#118&#105&#100&#117&#97&#108&#46&#13&#10&#76&#101&#116 &#117&#115 &#105&#109&#97&#103&#105&#110&#101 &#97 pool &#111&#102 &#103&#101&#110&#101&#115&#46 &#49&#50 &#97&#114&#101 B &#97&#110&#100 &#49&#56 &#97&#114&#101 &#98&#46 Now remember &#84&#104&#101 &#115&#117&#109 &#111&#102 &#97&#108&#108 the alleles must equal 100%. So this &#109&#101&#97&#110&#115&#13&#10&#116&#104&#97&#116 &#116&#104&#101 &#116&#111&#116&#97&#108 &#105&#110 this case <a href="http://cannabica.net/shishkaberryseedsforsale.shtml" title="Shishkaberryseedsforsale" alt="Shishkaberryseedsforsale" >Shishkaberryseedsforsale</a> is 12 + 18 = &#51&#48&#46 &#83&#111 &#51&#48 &#105&#115 &#49&#48&#48&#37&#46&#13&#10&#73&#102 we want to find the frequencies of B and &#98 &#97&#110&#100 &#116&#104&#101&#13&#10&#103&#101&#110&#111&#116&#121&#112&#105&#99 &#102&#114&#101&#113&#117&#101&#110&#99&#105&#101&#115 of B, Bb and b &#116&#104&#101&#110 &#119&#101 &#119&#105&#108&#108 &#104&#97&#118&#101 &#116&#111 apply the standard formula &#116&#104&#97&#116 &#119&#101 &#104&#97&#118&#101 &#106&#117&#115&#116 been &#115&#104&#111&#119&#110&#46&#13&#10&#102 &#40&#66&#41 &#61 &#49&#50&#47&#51&#48 = 0.4 = 40% f (b) &#61 &#49&#56&#47&#51&#48 &#61 &#48&#46&#54 = 60% Both add to make 100%. Now we know their ratios.<br> So, c + &#100 &#61 &#48&#46&#52 &#43 0.6 = 1 We have proven that &#99 &#43 &#100 &#109&#117&#115&#116 equal 1.<br> Very straightforward, yes. 296 Remember that all the random &#112&#111&#115&#115&#105&#98&#108&#101 &#99&#111&#109&#98&#105&#110&#97&#116&#105&#111&#110&#115 &#111&#102 &#116&#104&#101 members of a &#112&#111&#112&#117&#108&#97&#116&#105&#111&#110 &#119&#111&#117&#108&#100 &#101&#113&#117&#97&#108 &#40&#99 x &#99&#41 &#43 &#50&#99&#100 &#43 (d x d), or (c+d) X (c+d) Then, c + &#100 &#61 &#48&#46&#52 &#43 0.6 = &#49&#13&#10&#65&#110&#100 &#40&#99 &#120 &#99&#41 + 2cd + (d &#120 &#100&#41&#13&#10&#61 &#66&#66 &#43 Bb + bb = .24 &#43 &#46&#52&#56 &#43 &#46&#51&#48 = 1 This &#109&#101&#97&#110&#115 &#116&#104&#97&#116 &#116&#104&#101 &#112&#111&#112&#117&#108&#97&#116&#105&#111&#110 &#99&#97&#110 increase in &#115&#105&#122&#101&#44 &#98&#117&#116 &#116&#104&#101&#13&#10&#102&#114&#101&#113&#117&#101&#110&#99&#105&#101&#115 &#111&#102 B and b will stay the same.<br> Now, &#115&#117&#112&#112&#111&#115&#101 &#119&#101 &#98&#114&#101&#97&#107 &#116&#104&#101 &#52&#116&#104 law about not introducing another population into this one. Let &#117&#115 &#115&#97&#121 &#116&#104&#97&#116 &#119&#101 add 4 more b. b &#43 &#98 &#43 &#98 + b &#101&#110&#116&#101&#114 &#116&#104&#101 &#112&#111&#111&#108&#46 &#84&#104&#105&#115 brings our total up to 34 instead of 30. What will the gene and genotypic frequencies be? f (B) = 12/34 &#61 &#46&#51&#53 &#61 &#51&#53 % f &#40&#98&#41 &#61 &#50&#50&#47&#51&#52 &#61 .65 = 65% f (BB) = .12, f (Bb) &#61 &#46&#50&#51 &#97&#110&#100 &#102 (bb) = .42 Oppss, .42 does not equal &#49&#46 &#84&#104&#105&#115 &#109&#101&#97&#110&#115 &#116&#104&#97&#116 the Equilibrium law fails if the 4th law is &#110&#111&#116 &#109&#101&#116&#46 &#87&#104&#101&#110 &#116&#104&#101 new &#103&#101&#110&#101&#115 &#101&#110&#116&#101&#114&#101&#100 &#116&#104&#101 &#112&#111&#111&#108 it resulted in a change of the population’s gene frequencies. However if 297 no other &#112&#111&#112&#117&#108&#97&#116&#105&#111&#110&#115 &#119&#104&#101&#114&#101 &#105&#110&#116&#114&#111&#100&#117&#99&#101&#100 &#116&#104&#101&#110 the frequency of .42 would be maintained generation after generation. However we would like to point out that we used a very small pool in the above &#101&#120&#97&#109&#112&#108&#101&#46 &#73&#102 &#116&#104&#101 &#112&#111&#111&#108 were much &#108&#97&#114&#103&#101&#114 &#116&#104&#101&#110 &#116&#104&#101&#13&#10&#110&#117&#109&#98&#101&#114 &#111&#102 changes, even if &#111&#110&#101 &#111&#114 &#116&#119&#111 &#110&#101&#119 genes &#106&#117&#109&#112&#101&#100 &#105&#110&#44 &#119&#111&#117&#108&#100 &#98&#101&#13&#10&#105&#110&#115&#105&#103&#110&#105&#102&#105&#99&#97&#110&#116&#46 &#89&#111&#117 could calculate it, but the change would be on &#97&#110&#13&#10&#101&#120&#116&#114&#101&#109&#101&#108&#121 &#108&#111&#119 &#108&#101&#118&#101 </p><a href="http://cannabica.net/pdf/seaofgreenpotgrowingtips.pdf">seaofgreenpotgrowingtips</a></p> <h2> To To Seeds To</h2> <p>ATIVE GROWTH -PRE-FLOWERING -EARLY SEXING METHODS -WHEN TO FLOWER -THE ALL IMPORTANT 12/12 -PROBLEMS WITH 12/12 -HOW TO SEX YOUR PLANTS -HERMAPHRODITES -FLOWERING 14 Chapter 8 : ADVANCED INDOOR SOIL BASED GROW METHODS -SOG -ScrOG -CABINET GROWING -ADVANCED SET-UPS -PERPETUAL GROW CYCLE Chapter 9 : BASIC HYDROPONICS - THE GROWER AND THE GROWING MEDIUM - HYDROPONICS SET-UPS -HYDROPONICS NUTRIENTS -HYDROPONICS GROWING MEDIUMS -CANNABIS AND HYDROPONICS -THE BUBBLER Chapter 10 : OUTDOOR GROWING -THE GROWER AND THE GREAT OUTDOORS -CARING FOR OUTDOOR PLANTS 15 Chapter 11 : THE BASICS OF PLANT CARE -THINNING -LIGHT BENDING -PRUNING -BUSHES -TRAINING -INCREASING YIELD Chapter 12 : PREDATORS AND PESTS -INDEX OF PESTS -CLEANING THE GROW ROOM Chapter 13 : PROBLEM SOLVER - PLANT PROBLEMS AND HOW TO SOLVE THEM - POT-BOUND AND ROOT-BOUND -LOCKOUT -BAD GENETICS 16 Chapter 14: HARVESTING AND CURING YOUR BUD - INDICA HARVEST -SATIVA HARVEST -FAN LEAVES, LEAVES AND TRIM -CURING Chapter 15: BREEDING - MAKING SEEDS -POLLEN -SIMPLE BREEDING -HOW TO CONTINUE A STRAIN THROUGH SEED -HOW TO MAKE A SIMPLE HYBRID -AN INTRODUCTION INTO BASIC GENETICS -GENE PAIRS -DOMINANT AND RECESSIVE -MODIFYING GENES -PARTIAL DOMINANCE -HARDY-WEINBERG EQUILIBRIUM -THE TEST CROSS -HARDY-WEINBERG EQUILIBRIUM PART 2 17 -HOW TO TRUE BREED A STRAIN -CUBING AND BACKCROSSING -SELFING Chapter 16: STRAIN INDEX Chapter 17: HOW TO MAKE HASH - HOW TO GATHER THE STALKED CAPITATE TRICHOMES -SKUFF -BASICS OF SCREENING -PROPER SCREENING METHODS -HOW TO PRESS SKUFF INTO HASH GLOSSARY OF TERMS INDEX 18 FOREWORD The book is a grow bible. There is still much work that needs to be done to provide something that is truly of bible size, but that will come in time. The reason why I know this is because cannabis suppression has suspended cannabis information gathering over the past 60 years. I can safely say that you can find books on Roses that are 10 times thicker than this book with heaps more information. Roses are not illegal in most countries, so scientists are free to explore the Rose. Sadly the same can not be said for cannabis......until now. The Cannabis Grow Bible (CGB for short) is new. New, in that the book is one of a kind. Those who are willing to take serious risks in getting you this information have discovered most of what you will read and learn here. It is fine and easy for me to compile the book and write it. I am not at risk by printing this book, but those who grew out hundreds of plants in their basement to provide me with raw data on this subject matter are at risk. It is with their help that they have been able to help me parse what is real and what is not in the world of growing cannabis. They have helped take facts and figures and use these to put together a book that would truly help someone grow bigger buds. The results have been outstanding and I am very thankful for what they h</p> <p> </p> </DIV> <DIV id=foot> Valid <a href="http://validator.w3.org/check?uri=referer" target="_blank">HTML 4.01</a> <a href="http://jigsaw.w3.org/css-validator/check/referer" target="_blank">CSS</a> - <a href="http://cannabica.net/to germinate marijuana seeds.shtml" title="To Germinate Marijuana Seeds" alt="To Germinate Marijuana Seeds" >To Germinate Marijuana Seeds</a>, Powered by the magic team 2/6/2012 2:51:32 PM</DIV> </DIV> <DIV class=Bottomshadow></DIV> </DIV> </body>