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<body><DIV class=Contentbg> <DIV class=Topborder></Div> <DIV id=BigImage> ivapor stick </DIV> <DIV class=Bottomshadow></DIV> <DIV class=Bottomshadow2><h1> trippy stix for sale Marijuana Seeds Amsterdam </h1></DIV> </DIV> <DIV class=Contentbg> <DIV class=Topborder></Div> <DIV id=Content> <A name="content"></a> <DIV id=SideInfo> <div id=othernavcontainer> <div id=othernav> <H3></H3> <ul class=navlist> <li><li><a href="http://cannabica.net/ordertrippystick.shtml" title="Ordertrippystick" alt="Ordertrippystick" >Ordertrippystick</a></li><li><a href="http://cannabica.net/germinate marijuana seeds.shtml" title="Seeds Kc33 Seeds Kc33 Marijuana" alt="Seeds Kc33 Seeds Kc33 Marijuana" >Seeds Kc33 Seeds Kc33 Marijuana</a></li><li><a href="http://cannabica.net/vaporizerstickformarijuana.shtml" title="Vaporizerstickformarijuana" alt="Vaporizerstickformarijuana" >Vaporizerstickformarijuana</a></li><li><a href="http://cannabica.net/trippystixforsale.shtml" title="Trippystixforsale" alt="Trippystixforsale" >Trippystixforsale</a></li><li><a href="http://cannabica.net/trippysticksforsale.shtml" title="Trippysticksforsale" alt="Trippysticksforsale" >Trippysticksforsale</a></li><li><a href="http://cannabica.net/ordertrippystickonline.shtml" title="Ordertrippystickonline" alt="Ordertrippystickonline" >Ordertrippystickonline</a></li><li><a href="http://cannabica.net/howtomakeatrippystick.shtml" title="Howtomakeatrippystick" alt="Howtomakeatrippystick" >Howtomakeatrippystick</a></li><li><a href="http://cannabica.net/trippystickpotency.shtml" title="Trippystickpotency" alt="Trippystickpotency" >Trippystickpotency</a></li><li><a href="http://cannabica.net/nlseedsak47automaticpaypal.shtml" title="Nlseedsak47automaticpaypal" alt="Nlseedsak47automaticpaypal" >Nlseedsak47automaticpaypal</a></li><li><a href="http://cannabica.net/sensi.shtml" title="Sensi" alt="Sensi" >Sensi</a></li><li><a href="http://cannabica.net/sitemap.aspx">Sitemap</a></li><li><a href="http://cannabica.net/sitemap.xml">Sitemap XML</a></li><li><a href="http://cannabica.net/rss/">RSS</a></li><li><a href="http://cannabica.net/mobile.aspx">Mobile version</a></li></li> <li></li> </ul> <H3> Sprout Marijuana Seeds</H3> <ul class=navlist> <li></li> </ul> </div> </div> </DIV> <DIV class=Contentarea> <h1>TRIPPY BUY BUY</h1> <h3> mazar-i-sharif cannabis strain</h3> <p><a href="/ivaportrippystickcartridge.shtml"><img border="3" src="/images/cannabisworld.jpg" alt=" Ivaportrippystickcartridge"></a></p> <p> &#73 &#97&#109 &#100&#111&#119&#110 to 8 Females only out of a 30 seed &#111&#114&#100&#101&#114&#46 &#65&#110&#100 &#110&#111&#116 &#116&#104&#101 first &#80&#73&#78&#75 &#72&#65&#73&#82&#46 &#65&#108&#108 &#110&#111&#114&#109&#97&#108 color. :( Finishing out the budding of them <a href="http://cannabica.net/therealtrippystixcom.shtml" title="Therealtrippystixcom" alt="Therealtrippystixcom" >Therealtrippystixcom</a> to sample the quality. Since &#116&#104&#101&#121 &#100&#105&#100 &#110&#111&#116 &#112&#114&#111&#100&#117&#99&#101 the &#112&#105&#110&#107 &#104&#97&#105&#114&#115 &#44 &#73 &#119&#111&#110&#100&#101&#114 did I get the strain I paid for? 3 of the males fully showed & produced pollen &#119&#104&#105&#108&#101 &#117&#110&#100&#101&#114 &#50&#52 &#104&#114&#115 light.<br> That I have &#110&#101&#118&#101&#114&#13&#10&#115&#101&#101&#110&#46 &#73 &#115&#97&#118&#101&#100 &#116&#104&#101 &#112&#111&#108&#108&#101&#110 &#102&#114&#111&#109 &#116&#104&#111&#115&#101 &#51 males. There were a lot of hermaphrodites, at least 8. Some of &#116&#104&#101&#13&#10&#102&#101&#109&#97&#108&#101&#115 &#115&#104&#111&#119&#101&#100 &#117&#110&#100&#101&#114 &#50&#52 hour also. I have dropped the females all down to 10 &#104&#111&#117&#114&#115 &#97 &#100&#97&#121 &#116&#111 finish them out. All &#109&#97&#108&#101&#115 &#38 &#104&#101&#114&#109&#105&#101&#115 &#97&#114&#101 dead. &#73 &#104&#111&#112&#101 &#116&#104&#101&#121 &#100&#105&#100 not send me industrial hemp!!!! &#79&#114 &#109&#97&#121&#98&#101 &#115&#116&#114&#97&#105&#103&#104&#116&#13&#10&#82&#117&#100&#101&#114&#97&#108&#105&#115&#63 &#66&#117&#116 &#116&#104&#101&#121 finish at different rates so I &#119&#111&#110&#100&#101&#114 &#119&#97&#115 &#105&#116 &#115&#116&#97&#98&#108&#101 at all? Or &#109&#97&#121&#98&#101 &#73 &#119&#97&#115 &#115&#101&#110&#116 different types of seed? I thought that F1 &#104&#121&#98&#105&#114&#100 &#115&#101&#101&#100&#115 &#119&#111&#117&#108&#100 &#112&#114&#111&#100&#117&#99&#101 even &#116&#114&#97&#105&#116&#115&#63 &#73 &#116&#104&#111&#117&#103&#104&#116 &#116&#104&#97&#116 the traits &#119&#111&#117&#108&#100 &#110&#111&#116&#13&#10&#115&#101&#103&#114&#101&#103&#97&#116&#101 &#117&#110&#108&#101&#115&#115 &#73 &#115&#101&#101&#100&#101&#100 the F1's? ” – Country &#66&#111&#121 <a href="http://cannabica.net/germinate marijuana seeds.shtml" title="Germinate Marijuana Seeds" alt="Germinate Marijuana Seeds" >Germinate Marijuana Seeds</a></p> <h2> trippy stick canada</h2> <p>“I've been growing both Shishke & Sweetooth for a while and would choose 'Sweetooth' over Shishke after having both of them for over a year. The Sweetooth is a large yielder (50 grams a sq./ft). Sweetooth makes large contiguous colas even on short plants. The visual of the cured bud is great. The Shishke is a heavy yielder; I haven't quite decided if the Sweetooth can out yield the Shishke in perfect temperature conditions. Shishke and Sweetooth are both blue berry hybrids and I notice a lot of similarities in the veg growth of the two plants, but the Sweetooth has a sweet scent (no ozone required), and can take more stress (it gets hot where I live). Shishke smells kinda musky, doesn't like heat. If heat stressed it will herm, clones from the same mom in a different garden have no herms ... otherwise, very easy plant to grow and the high is strong & up. The high from the Sweetooth is just like the SOL ad "keeps us giddy & high all day". Both plants have fairly "up" buzz, the Shishke has a hashy taste, and the Sweetooth is sweet & berry.” - Shiva<a href="http://cannabica.net/pdf/overgrow.pdf">overgrow</a></p> <h2> marijuana seeds amsterdam</h2> <p><p align="center"> which there is no change &#105&#110 &#116&#104&#101 &#103&#101&#110&#101 &#112&#111&#111&#108&#46 This means that there can be no evolution. For a test example let us consider a population &#119&#104&#111&#115&#101 &#103&#101&#110&#101&#13&#10&#112&#111&#111&#108 &#99&#111&#110&#116&#97&#105&#110&#115 &#116&#104&#101 &#97&#108&#108&#101&#108&#101&#115 B and b. Assign the letter c to the &#102&#114&#101&#113&#117&#101&#110&#99&#121&#13&#10&#111&#102 &#116&#104&#101 &#100&#111&#109&#105&#110&#97&#110&#116 &#97&#108&#108&#101&#108&#101 B and the letter d to &#116&#104&#101 &#102&#114&#101&#113&#117&#101&#110&#99&#121 &#111&#102 &#116&#104&#101&#13&#10&#114&#101&#99&#101&#115&#115&#105&#118&#101 allele b. In &#109&#111&#115&#116 &#99&#97&#115&#101&#115 &#121&#111&#117 &#119&#105&#108&#108 &#102&#105&#110&#100 &#116&#104&#97&#116 c and d are actually notated as p and &#113 &#98&#121 &#99&#111&#110&#118&#101&#110&#116&#105&#111&#110 &#105&#110 &#115&#99&#105&#101&#110&#99&#101&#44 but for this example we will use c and d.<br>] The sum of all the alleles must equal 100%. So c &#43 &#100 &#61 &#49&#46&#13&#10&#65&#108&#108 the random possible combinations of &#116&#104&#101 &#109&#101&#109&#98&#101&#114&#115 &#111&#102 &#97&#13&#10&#112&#111&#112&#117&#108&#97&#116&#105&#111&#110 would equal (c x c) + 2cd &#43 &#40&#100 &#120 &#100&#41&#46 Which can &#97&#108&#115&#111 &#98&#101&#13&#10&#101&#120&#112&#114&#101&#115&#115&#101&#100 &#97&#115&#58&#13&#10&#40&#99&#43&#100&#41 &#88 (c+d) We will explain &#116&#104&#105&#115 &#105&#110 &#100&#101&#116&#97&#105&#108 &#105&#110 moment, but &#105&#116 &#105&#115 &#98&#101&#115&#116 &#116&#111 know &#105&#116 &#102&#111&#114&#13&#10&#110&#111&#119&#46&#13&#10&#84&#104&#101 &#102&#114&#101&#113&#117&#101&#110&#99&#105&#101&#115 &#111&#102 &#66 and b will remain unchanged generation after generation if: 1. &#84&#104&#101 &#112&#111&#112&#117&#108&#97&#116&#105&#111&#110 &#105&#115 &#108&#97&#114&#103&#101 enough. 2. There are no mutations. 295 3. There &#97&#114&#101 &#110&#111 &#112&#114&#101&#102&#101&#114&#101&#110&#99&#101&#115&#46 &#70&#111&#114 example a BB male does not prefer a bb female by its nature. 4. No &#111&#116&#104&#101&#114 &#111&#117&#116&#115&#105&#100&#101 &#112&#111&#112&#117&#108&#97&#116&#105&#111&#110 &#101&#120&#99&#104&#97&#110&#103&#101&#115 genes &#119&#105&#116&#104 &#116&#104&#105&#115 &#109&#111&#100&#101&#108&#46&#13&#10&#53&#46 &#78&#97&#116&#117&#114&#97&#108 selection must not favor &#97&#110&#121 &#115&#112&#101&#99&#105&#102&#105&#99 &#105&#110&#100&#105&#118&#105&#100&#117&#97&#108&#46&#13&#10&#76&#101&#116 &#117&#115 imagine a pool of genes.<br> 12 are B &#97&#110&#100 &#49&#56 &#97&#114&#101 &#98&#46 Now remember The sum of &#97&#108&#108 &#116&#104&#101 &#97&#108&#108&#101&#108&#101&#115 &#109&#117&#115&#116 equal 100%. So this means that the total in this &#99&#97&#115&#101 &#105&#115 &#49&#50 &#43 18 = 30. So 30 is 100%.<br> If we want to find the frequencies of &#66 &#97&#110&#100 &#98 &#97&#110&#100 the genotypic frequencies of B, Bb and &#98 &#116&#104&#101&#110 &#119&#101 &#119&#105&#108&#108 &#104&#97&#118&#101 to &#97&#112&#112&#108&#121 &#116&#104&#101&#13&#10&#115&#116&#97&#110&#100&#97&#114&#100 &#102&#111&#114&#109&#117&#108&#97 &#116&#104&#97&#116 we have just been shown. f (B) = 12/30 &#61 &#48&#46&#52 &#61 &#52&#48&#37&#13&#10&#102 (b) = 18/30 = 0.6 = 60% Both add &#116&#111 &#109&#97&#107&#101 &#49&#48&#48&#37&#46 &#78&#111&#119 &#119&#101 know &#116&#104&#101&#105&#114 &#114&#97&#116&#105&#111&#115&#46&#13&#10&#83&#111&#44&#13&#10&#99 &#43 &#100 = 0.4 + 0.6 = 1 We &#104&#97&#118&#101 &#112&#114&#111&#118&#101&#110 &#116&#104&#97&#116 &#99 + d must equal 1. Very straightforward, &#121&#101&#115&#46&#13&#10&#50&#57&#54&#13&#10&#82&#101&#109&#101&#109&#98&#101&#114 &#116&#104&#97&#116 &#97&#108&#108 &#116&#104&#101 random possible combinations of &#116&#104&#101 &#109&#101&#109&#98&#101&#114&#115&#13&#10&#111&#102 &#97 &#112&#111&#112&#117&#108&#97&#116&#105&#111&#110 would equal (c x &#99&#41 &#43 &#50&#99&#100 &#43 (d x d), or (c+d) X (c+d) Then, &#99 &#43 &#100 &#61 0.4 + 0.6 = 1 And (c x c) + &#50&#99&#100 &#43 &#40&#100 &#120 &#100&#41&#13&#10&#61 &#66&#66 + Bb &#43 &#98&#98&#13&#10&#61 &#46&#50&#52 &#43 .48 + .30 = &#49&#13&#10&#84&#104&#105&#115 &#109&#101&#97&#110&#115 &#116&#104&#97&#116 &#116&#104&#101 population can increase in size, but the frequencies &#111&#102 &#66 &#97&#110&#100 &#98 &#119&#105&#108&#108 stay the &#115&#97&#109&#101&#46&#13&#10&#78&#111&#119&#44 &#115&#117&#112&#112&#111&#115&#101 &#119&#101 &#98&#114&#101&#97&#107 &#116&#104&#101 4th law about not introducing another population into this one. Let us say that we add 4 more b. b + &#98 &#43 &#98 &#43 &#98 enter the pool. This brings our total up to 34 &#105&#110&#115&#116&#101&#97&#100 &#111&#102&#13&#10&#51&#48&#46 &#87&#104&#97&#116 &#119&#105&#108&#108 the gene and genotypic frequencies be? f (B) = 12/34 = &#46&#51&#53 &#61 &#51&#53 &#37&#13&#10&#102 (b) = 22/34 = .65 = 65% f &#40&#66&#66&#41 &#61 &#46&#49&#50&#44 &#102 (Bb) = &#46&#50&#51 &#97&#110&#100 &#102 &#40&#98&#98&#41 = .42 Oppss, &#46&#52&#50 &#100&#111&#101&#115 &#110&#111&#116 &#101&#113&#117&#97&#108 1. This means that the Equilibrium law fails if &#116&#104&#101 &#52&#116&#104 &#108&#97&#119 &#105&#115 not met. When the new genes entered &#116&#104&#101 &#112&#111&#111&#108 &#105&#116&#13&#10&#114&#101&#115&#117&#108&#116&#101&#100 &#105&#110 a &#99&#104&#97&#110&#103&#101 &#111&#102 &#116&#104&#101 &#112&#111&#112&#117&#108&#97&#116&#105&#111&#110&#8217&#115 gene frequencies. However if 297 no other populations where introduced then the frequency of &#46&#52&#50 &#119&#111&#117&#108&#100&#13&#10&#98&#101 &#109&#97&#105&#110&#116&#97&#105&#110&#101&#100 &#103&#101&#110&#101&#114&#97&#116&#105&#111&#110 after &#103&#101&#110&#101&#114&#97&#116&#105&#111&#110&#46&#13&#10&#72&#111&#119&#101&#118&#101&#114 &#119&#101 &#119&#111&#117&#108&#100 &#108&#105&#107&#101 to point out that we &#117&#115&#101&#100 &#97 &#118&#101&#114&#121 &#115&#109&#97&#108&#108&#13&#10&#112&#111&#111&#108 in &#116&#104&#101 &#97&#98&#111&#118&#101 &#101&#120&#97&#109&#112&#108&#101&#46 &#73&#102 &#116&#104&#101 pool were much larger then &#116&#104&#101&#13&#10&#110&#117&#109&#98&#101&#114 &#111&#102 &#99&#104&#97&#110&#103&#101&#115&#44 &#101&#118&#101&#110 &#105&#102 &#111&#110&#101 or two new &#103&#101&#110&#101&#115 &#106&#117&#109&#112&#101&#100 &#105&#110&#44 &#119&#111&#117&#108&#100 &#98&#101&#13&#10&#105&#110&#115&#105&#103&#110&#105&#102&#105&#99&#97&#110&#116&#46 You &#99&#111&#117&#108&#100 &#99&#97&#108&#99&#117&#108&#97&#116&#101 &#105&#116&#44 &#98&#117&#116 the change would be &#111&#110 &#97&#110&#13&#10&#101&#120&#116&#114&#101&#109&#101&#108&#121 &#108&#111&#119 &#108&#101&#118&#101&#119&#104&#105&#99&#104 there is no change in the gene &#112&#111&#111&#108&#46 &#84&#104&#105&#115 &#109&#101&#97&#110&#115 &#116&#104&#97&#116&#13&#10&#116&#104&#101&#114&#101 can be no evolution. For a test &#101&#120&#97&#109&#112&#108&#101 &#108&#101&#116 &#117&#115 &#99&#111&#110&#115&#105&#100&#101&#114 a &#112&#111&#112&#117&#108&#97&#116&#105&#111&#110 &#119&#104&#111&#115&#101 &#103&#101&#110&#101&#13&#10&#112&#111&#111&#108 &#99&#111&#110&#116&#97&#105&#110&#115 the alleles B &#97&#110&#100 &#98&#46 &#65&#115&#115&#105&#103&#110 &#116&#104&#101 letter &#99 &#116&#111 &#116&#104&#101 &#102&#114&#101&#113&#117&#101&#110&#99&#121&#13&#10&#111&#102 the dominant &#97&#108&#108&#101&#108&#101 &#66 &#97&#110&#100 &#116&#104&#101 letter d &#116&#111 &#116&#104&#101 &#102&#114&#101&#113&#117&#101&#110&#99&#121 &#111&#102 the recessive &#97&#108&#108&#101&#108&#101 &#98&#46&#13&#10&#73&#110 &#109&#111&#115&#116 &#99&#97&#115&#101&#115 you will find that c and d are actually notated as p and q by convention in science, &#98&#117&#116 &#102&#111&#114 &#116&#104&#105&#115 &#101&#120&#97&#109&#112&#108&#101 we &#119&#105&#108&#108 &#117&#115&#101 &#99&#13&#10&#97&#110&#100 &#100&#46&#93&#13&#10&#84&#104&#101 sum of all the alleles must equal 100%. So c &#43 &#100 &#61 &#49&#46&#13&#10&#65&#108&#108 the random possible &#99&#111&#109&#98&#105&#110&#97&#116&#105&#111&#110&#115 &#111&#102 &#116&#104&#101 &#109&#101&#109&#98&#101&#114&#115 of &#97&#13&#10&#112&#111&#112&#117&#108&#97&#116&#105&#111&#110 &#119&#111&#117&#108&#100 &#101&#113&#117&#97&#108 &#40&#99 <a href="http://cannabica.net/ivaportrippystickforsale.shtml" title="Ivaportrippystickforsale" alt="Ivaportrippystickforsale" >Ivaportrippystickforsale</a> x c) + 2cd &#43 &#40&#100 &#120 &#100&#41&#46 Which can also be expressed as: (c+d) X (c+d) We will explain this in detail in moment, but it &#105&#115 &#98&#101&#115&#116 &#116&#111 &#107&#110&#111&#119 it for now.<br> The frequencies of B &#97&#110&#100 &#98 &#119&#105&#108&#108 &#114&#101&#109&#97&#105&#110 unchanged &#103&#101&#110&#101&#114&#97&#116&#105&#111&#110 &#97&#102&#116&#101&#114&#13&#10&#103&#101&#110&#101&#114&#97&#116&#105&#111&#110 &#105&#102&#58&#13&#10&#49&#46 &#84&#104&#101 population is large enough. 2. There are no mutations. 295 3. There are no preferences. For &#101&#120&#97&#109&#112&#108&#101 &#97 &#66&#66 &#109&#97&#108&#101 does not prefer a bb female by its nature. 4. &#78&#111 &#111&#116&#104&#101&#114 &#111&#117&#116&#115&#105&#100&#101 &#112&#111&#112&#117&#108&#97&#116&#105&#111&#110 &#101&#120&#99&#104&#97&#110&#103&#101&#115 genes with this model.<br> 5.<br> &#78&#97&#116&#117&#114&#97&#108 &#115&#101&#108&#101&#99&#116&#105&#111&#110 &#109&#117&#115&#116 &#110&#111&#116 favor any specific &#105&#110&#100&#105&#118&#105&#100&#117&#97&#108&#46&#13&#10&#76&#101&#116 &#117&#115 &#105&#109&#97&#103&#105&#110&#101 &#97 pool of genes. 12 &#97&#114&#101 &#66 &#97&#110&#100 &#49&#56 are &#98&#46 &#78&#111&#119&#13&#10&#114&#101&#109&#101&#109&#98&#101&#114 &#84&#104&#101 &#115&#117&#109 of all the alleles must equal 100%. So &#116&#104&#105&#115 &#109&#101&#97&#110&#115&#13&#10&#116&#104&#97&#116 &#116&#104&#101 &#116&#111&#116&#97&#108 in this case is 12 &#43 &#49&#56 &#61 &#51&#48&#46 So 30 is 100%. If we want to find the frequencies &#111&#102 &#66 &#97&#110&#100 &#98 and &#116&#104&#101&#13&#10&#103&#101&#110&#111&#116&#121&#112&#105&#99 &#102&#114&#101&#113&#117&#101&#110&#99&#105&#101&#115 &#111&#102 &#66&#44 Bb &#97&#110&#100 &#98 &#116&#104&#101&#110 &#119&#101 will have to apply the standard formula that we have just been shown. f (B) = 12/30 = &#48&#46&#52 &#61 &#52&#48&#37&#13&#10&#102 &#40&#98&#41 = 18/30 = 0.6 = 60% Both add to &#109&#97&#107&#101 &#49&#48&#48&#37&#46 &#78&#111&#119 &#119&#101 &#107&#110&#111&#119 their ratios. So, c &#43 &#100 &#61 &#48&#46&#52 + &#48&#46&#54 &#61 &#49&#13&#10&#87&#101 &#104&#97&#118&#101 proven that &#99 &#43 &#100 &#109&#117&#115&#116 equal 1. Very straightforward, yes. 296 Remember that all the &#114&#97&#110&#100&#111&#109 &#112&#111&#115&#115&#105&#98&#108&#101 &#99&#111&#109&#98&#105&#110&#97&#116&#105&#111&#110&#115 &#111&#102 the members of &#97 &#112&#111&#112&#117&#108&#97&#116&#105&#111&#110 &#119&#111&#117&#108&#100 &#101&#113&#117&#97&#108 (c x c) + &#50&#99&#100 &#43 &#40&#100 &#120 d), or (c+d) X &#40&#99&#43&#100&#41&#13&#10&#84&#104&#101&#110&#44 &#99 &#43 &#100 = 0.4 + &#48&#46&#54 &#61 &#49&#13&#10&#65&#110&#100 &#40&#99 x c) + 2cd + (d x d) = BB + Bb + bb = .24 + .48 + .30 = 1 This means that the &#112&#111&#112&#117&#108&#97&#116&#105&#111&#110 &#99&#97&#110 &#105&#110&#99&#114&#101&#97&#115&#101 &#105&#110 &#115&#105&#122&#101&#44 &#98&#117&#116 the frequencies of B and b will stay the same. Now, suppose &#119&#101 &#98&#114&#101&#97&#107 &#116&#104&#101 &#52&#116&#104 law about not introducing another population &#105&#110&#116&#111 &#116&#104&#105&#115 &#111&#110&#101&#46&#13&#10&#76&#101&#116 &#117&#115 say &#116&#104&#97&#116 &#119&#101 &#97&#100&#100 &#52 more b. b + b + b + b enter the pool. This brings &#111&#117&#114 &#116&#111&#116&#97&#108 &#117&#112 &#116&#111 &#51&#52 instead of 30. What will the gene &#97&#110&#100 &#103&#101&#110&#111&#116&#121&#112&#105&#99 &#102&#114&#101&#113&#117&#101&#110&#99&#105&#101&#115 &#98&#101&#63&#13&#10&#102 &#40&#66&#41 = 12/34 = .35 = 35 % f (b) = 22/34 = .65 &#61 &#54&#53&#37&#13&#10&#102 &#40&#66&#66&#41 &#61 .12, f (Bb) = .23 and &#102 &#40&#98&#98&#41 &#61 &#46&#52&#50&#13&#10&#79&#112&#112&#115&#115&#44 .42 &#100&#111&#101&#115 &#110&#111&#116 &#101&#113&#117&#97&#108 &#49&#46 This means that the Equilibrium law fails if &#116&#104&#101 &#52&#116&#104 &#108&#97&#119 &#105&#115 not met. &#87&#104&#101&#110 &#116&#104&#101 &#110&#101&#119 &#103&#101&#110&#101&#115 entered the pool it resulted in a change of the population’s gene frequencies. &#72&#111&#119&#101&#118&#101&#114 &#105&#102&#13&#10&#50&#57&#55&#13&#10&#110&#111 &#111&#116&#104&#101&#114 &#112&#111&#112&#117&#108&#97&#116&#105&#111&#110&#115 where introduced &#116&#104&#101&#110 &#116&#104&#101 &#102&#114&#101&#113&#117&#101&#110&#99&#121 &#111&#102 .42 would be maintained generation after generation. However &#119&#101 &#119&#111&#117&#108&#100 &#108&#105&#107&#101 &#116&#111 point out that we used a very small pool in the above example.<br> If the pool were &#109&#117&#99&#104 &#108&#97&#114&#103&#101&#114 &#116&#104&#101&#110 &#116&#104&#101&#13&#10&#110&#117&#109&#98&#101&#114 &#111&#102 changes, even &#105&#102 &#111&#110&#101 &#111&#114 &#116&#119&#111 new genes jumped in, would be insignificant. You could calculate it, &#98&#117&#116 &#116&#104&#101 &#99&#104&#97&#110&#103&#101 &#119&#111&#117&#108&#100 be on an extremely low levewhich there is no &#99&#104&#97&#110&#103&#101 &#105&#110 &#116&#104&#101 &#103&#101&#110&#101 pool. This means that there can be &#110&#111 &#101&#118&#111&#108&#117&#116&#105&#111&#110&#46&#13&#10&#70&#111&#114 &#97 &#116&#101&#115&#116 example &#108&#101&#116 &#117&#115 &#99&#111&#110&#115&#105&#100&#101&#114 &#97 &#112&#111&#112&#117&#108&#97&#116&#105&#111&#110 whose gene pool contains the alleles B and b. &#65&#115&#115&#105&#103&#110 &#116&#104&#101 &#108&#101&#116&#116&#101&#114 &#99 to the &#102&#114&#101&#113&#117&#101&#110&#99&#121&#13&#10&#111&#102 &#116&#104&#101 &#100&#111&#109&#105&#110&#97&#110&#116 &#97&#108&#108&#101&#108&#101 B and &#116&#104&#101 &#108&#101&#116&#116&#101&#114 &#100 &#116&#111 &#116&#104&#101 &#102&#114&#101&#113&#117&#101&#110&#99&#121 of the recessive allele b.<br> In most &#99&#97&#115&#101&#115 &#121&#111&#117 &#119&#105&#108&#108 &#102&#105&#110&#100 that c and d are actually notated as p and q &#98&#121 &#99&#111&#110&#118&#101&#110&#116&#105&#111&#110 &#105&#110 &#115&#99&#105&#101&#110&#99&#101&#44 &#98&#117&#116 for this example we will use c and d.<br> The sum of all the alleles must equal 100%. So c + d = 1. All the random &#112&#111&#115&#115&#105&#98&#108&#101 &#99&#111&#109&#98&#105&#110&#97&#116&#105&#111&#110&#115 &#111&#102 &#116&#104&#101 members of &#97&#13&#10&#112&#111&#112&#117&#108&#97&#116&#105&#111&#110 &#119&#111&#117&#108&#100 &#101&#113&#117&#97&#108 &#40&#99 x c) + 2cd + (d x d). Which can also be expressed as: (c+d) X (c+d) We &#119&#105&#108&#108 &#101&#120&#112&#108&#97&#105&#110 &#116&#104&#105&#115 &#105&#110 detail in &#109&#111&#109&#101&#110&#116&#44 &#98&#117&#116 &#105&#116 &#105&#115 best to know it for now. The frequencies of B and b will remain unchanged &#103&#101&#110&#101&#114&#97&#116&#105&#111&#110 &#97&#102&#116&#101&#114&#13&#10&#103&#101&#110&#101&#114&#97&#116&#105&#111&#110 &#105&#102&#58&#13&#10&#49&#46 &#84&#104&#101 population is large enough. 2. There &#97&#114&#101 &#110&#111 &#109&#117&#116&#97&#116&#105&#111&#110&#115&#46&#13&#10&#50&#57&#53&#13&#10&#51&#46 &#84&#104&#101&#114&#101 are no preferences. &#70&#111&#114 &#101&#120&#97&#109&#112&#108&#101 &#97 &#66&#66 male does not prefer a bb female by its nature. 4. No other outside &#112&#111&#112&#117&#108&#97&#116&#105&#111&#110 &#101&#120&#99&#104&#97&#110&#103&#101&#115 &#103&#101&#110&#101&#115 &#119&#105&#116&#104 this model. 5. Natural selection must &#110&#111&#116 &#102&#97&#118&#111&#114 &#97&#110&#121 &#115&#112&#101&#99&#105&#102&#105&#99 &#105&#110&#100&#105&#118&#105&#100&#117&#97&#108&#46&#13&#10&#76&#101&#116 &#117&#115 imagine &#97 &#112&#111&#111&#108 &#111&#102 &#103&#101&#110&#101&#115&#46 12 are B and 18 are b. &#78&#111&#119&#13&#10&#114&#101&#109&#101&#109&#98&#101&#114 &#84&#104&#101 &#115&#117&#109 &#111&#102 all the alleles must equal 100%. So this means that the total in this case is 12 + &#49&#56 &#61 &#51&#48&#46 &#83&#111 30 is 100%. If we want &#116&#111 &#102&#105&#110&#100 &#116&#104&#101 &#102&#114&#101&#113&#117&#101&#110&#99&#105&#101&#115 of B and b and &#116&#104&#101&#13&#10&#103&#101&#110&#111&#116&#121&#112&#105&#99 &#102&#114&#101&#113&#117&#101&#110&#99&#105&#101&#115 &#111&#102 &#66&#44 Bb and b &#116&#104&#101&#110 &#119&#101 &#119&#105&#108&#108 &#104&#97&#118&#101 &#116&#111 &#97&#112&#112&#108&#121 the standard formula that we &#104&#97&#118&#101 &#106&#117&#115&#116 &#98&#101&#101&#110 &#115&#104&#111&#119&#110&#46&#13&#10&#102 &#40&#66&#41 &#61 &#49&#50&#47&#51&#48 = 0.4 = 40% f (b) = &#49&#56&#47&#51&#48 &#61 &#48&#46&#54 &#61 60% Both add to make 100%. Now we know their ratios. So, c + d &#61 &#48&#46&#52 &#43 &#48&#46&#54 = 1 We have proven that c &#43 &#100 &#109&#117&#115&#116 &#101&#113&#117&#97&#108 &#49&#46&#13&#10&#86&#101&#114&#121 straightforward, yes.<br> 296 Remember that all the random &#112&#111&#115&#115&#105&#98&#108&#101 &#99&#111&#109&#98&#105&#110&#97&#116&#105&#111&#110&#115 &#111&#102 &#116&#104&#101 members of a population &#119&#111&#117&#108&#100 &#101&#113&#117&#97&#108 &#40&#99 &#120 c) + 2cd + (d x d), or (c+d) X &#40&#99&#43&#100&#41&#13&#10&#84&#104&#101&#110&#44 &#99 &#43 &#100 = 0.4 + &#48&#46&#54 &#61 &#49&#13&#10&#65&#110&#100 &#40&#99 x c) + 2cd + (d x d) = BB + Bb + bb = &#46&#50&#52 &#43 &#46&#52&#56 &#43 .30 = 1 This means that the &#112&#111&#112&#117&#108&#97&#116&#105&#111&#110 &#99&#97&#110 &#105&#110&#99&#114&#101&#97&#115&#101 &#105&#110 size, but the frequencies &#111&#102 &#66 &#97&#110&#100 &#98 &#119&#105&#108&#108 stay the &#115&#97&#109&#101&#46&#13&#10&#78&#111&#119&#44 &#115&#117&#112&#112&#111&#115&#101 &#119&#101 &#98&#114&#101&#97&#107 &#116&#104&#101 4th law &#97&#98&#111&#117&#116 &#110&#111&#116 &#105&#110&#116&#114&#111&#100&#117&#99&#105&#110&#103 &#97&#110&#111&#116&#104&#101&#114&#13&#10&#112&#111&#112&#117&#108&#97&#116&#105&#111&#110 into this one. Let us say that we add 4 more &#98&#46&#13&#10&#98 &#43 &#98 &#43 b + b enter the pool. &#84&#104&#105&#115 &#98&#114&#105&#110&#103&#115 &#111&#117&#114 &#116&#111&#116&#97&#108 up to 34 instead of 30. What will the gene and genotypic frequencies be? f (B) = 12/34 = &#46&#51&#53 &#61 &#51&#53 &#37&#13&#10&#102 (b) &#61 &#50&#50&#47&#51&#52 &#61 &#46&#54&#53 = 65% f (BB) = .12, &#102 &#40&#66&#98&#41 &#61 &#46&#50&#51 and f (bb) = &#46&#52&#50&#13&#10&#79&#112&#112&#115&#115&#44 &#46&#52&#50 &#100&#111&#101&#115 &#110&#111&#116 equal 1. This &#109&#101&#97&#110&#115 &#116&#104&#97&#116 &#116&#104&#101 &#69&#113&#117&#105&#108&#105&#98&#114&#105&#117&#109 law fails if the 4th &#108&#97&#119 &#105&#115 &#110&#111&#116 &#109&#101&#116&#46 When &#116&#104&#101 &#110&#101&#119 &#103&#101&#110&#101&#115 &#101&#110&#116&#101&#114&#101&#100 the pool it resulted in a change of the population’s <H2> Trippy Stick For Sale</H2> gene frequencies. However if 297 no other populations where introduced then the frequency of .42 would be maintained generation &#97&#102&#116&#101&#114 &#103&#101&#110&#101&#114&#97&#116&#105&#111&#110&#46&#13&#10&#72&#111&#119&#101&#118&#101&#114 &#119&#101 &#119&#111&#117&#108&#100 like to point out that &#119&#101 &#117&#115&#101&#100 &#97 &#118&#101&#114&#121 small pool &#105&#110 &#116&#104&#101 &#97&#98&#111&#118&#101 &#101&#120&#97&#109&#112&#108&#101&#46 If &#116&#104&#101 &#112&#111&#111&#108 &#119&#101&#114&#101 &#109&#117&#99&#104 larger then the number of changes, even if one or &#116&#119&#111 &#110&#101&#119 &#103&#101&#110&#101&#115 &#106&#117&#109&#112&#101&#100 in, would be insignificant.<br> You could calculate it, but &#116&#104&#101 &#99&#104&#97&#110&#103&#101 &#119&#111&#117&#108&#100 &#98&#101 on an extremely low levewhich there is no change in the gene pool. This means that there can be no &#101&#118&#111&#108&#117&#116&#105&#111&#110&#46&#13&#10&#70&#111&#114 &#97 &#116&#101&#115&#116 &#101&#120&#97&#109&#112&#108&#101 let &#117&#115 &#99&#111&#110&#115&#105&#100&#101&#114 &#97 &#112&#111&#112&#117&#108&#97&#116&#105&#111&#110 &#119&#104&#111&#115&#101 gene pool &#99&#111&#110&#116&#97&#105&#110&#115 &#116&#104&#101 &#97&#108&#108&#101&#108&#101&#115 &#66 and b. Assign the letter &#99 &#116&#111 &#116&#104&#101 &#102&#114&#101&#113&#117&#101&#110&#99&#121&#13&#10&#111&#102 the dominant &#97&#108&#108&#101&#108&#101 &#66 &#97&#110&#100 &#116&#104&#101 letter d to the frequency of &#116&#104&#101&#13&#10&#114&#101&#99&#101&#115&#115&#105&#118&#101 &#97&#108&#108&#101&#108&#101 &#98&#46&#13&#10&#73&#110 &#109&#111&#115&#116 cases &#121&#111&#117 &#119&#105&#108&#108 &#102&#105&#110&#100 &#116&#104&#97&#116 c and d are actually &#110&#111&#116&#97&#116&#101&#100&#13&#10&#97&#115 &#112 &#97&#110&#100 &#113 by &#99&#111&#110&#118&#101&#110&#116&#105&#111&#110 &#105&#110 &#115&#99&#105&#101&#110&#99&#101&#44 &#98&#117&#116 for this &#101&#120&#97&#109&#112&#108&#101 &#119&#101 &#119&#105&#108&#108 &#117&#115&#101 c and d. The &#115&#117&#109 &#111&#102 &#97&#108&#108 &#116&#104&#101 alleles &#109&#117&#115&#116 &#101&#113&#117&#97&#108 &#49&#48&#48&#37&#46&#13&#10&#83&#111 &#99 + d = 1. All the &#114&#97&#110&#100&#111&#109 &#112&#111&#115&#115&#105&#98&#108&#101 &#99&#111&#109&#98&#105&#110&#97&#116&#105&#111&#110&#115 &#111&#102 the members of a population would equal (c x c) + 2cd + (d x d). Which can also be expressed &#97&#115&#58&#13&#10&#40&#99&#43&#100&#41 &#88 &#40&#99&#43&#100&#41&#13&#10&#87&#101 &#119&#105&#108&#108 explain this in detail in moment, but it is best to know it for now. The frequencies of &#66 &#97&#110&#100 &#98 &#119&#105&#108&#108 remain unchanged generation after generation if: 1. The population is large enough. 2. There are no &#109&#117&#116&#97&#116&#105&#111&#110&#115&#46&#13&#10&#50&#57&#53&#13&#10&#51&#46 &#84&#104&#101&#114&#101 &#97&#114&#101 &#110&#111 preferences.<br> For &#101&#120&#97&#109&#112&#108&#101 &#97 &#66&#66 &#109&#97&#108&#101 does &#110&#111&#116 &#112&#114&#101&#102&#101&#114 &#97&#13&#10&#98&#98 &#102&#101&#109&#97&#108&#101 by its nature. 4. No other outside population exchanges genes with this model. 5. &#78&#97&#116&#117&#114&#97&#108 &#115&#101&#108&#101&#99&#116&#105&#111&#110 &#109&#117&#115&#116 &#110&#111&#116 &#102&#97&#118&#111&#114 any specific individual. Let us imagine a pool of genes. 12 are B and 18 are b. Now remember The sum of &#97&#108&#108 &#116&#104&#101 &#97&#108&#108&#101&#108&#101&#115 &#109&#117&#115&#116 &#101&#113&#117&#97&#108 100%. So this means that &#116&#104&#101 &#116&#111&#116&#97&#108 &#105&#110 &#116&#104&#105&#115 case is 12 &#43 &#49&#56 &#61 &#51&#48&#46 So 30 &#105&#115 &#49&#48&#48&#37&#46&#13&#10&#73&#102 &#119&#101 &#119&#97&#110&#116 to find the frequencies of &#66 &#97&#110&#100 &#98 &#97&#110&#100 the genotypic frequencies of B, &#66&#98 &#97&#110&#100 &#98 &#116&#104&#101&#110 we &#119&#105&#108&#108 &#104&#97&#118&#101 &#116&#111 &#97&#112&#112&#108&#121 the standard formula that we have just been &#115&#104&#111&#119&#110&#46&#13&#10&#102 &#40&#66&#41 &#61 &#49&#50&#47&#51&#48 = 0.4 = 40% f (b) = 18/30 = 0.6 = 60% Both add to make 100%. Now we know their &#114&#97&#116&#105&#111&#115&#46&#13&#10&#83&#111&#44&#13&#10&#99 &#43 &#100 &#61 0.4 + 0.6 = &#49&#13&#10&#87&#101 &#104&#97&#118&#101 &#112&#114&#111&#118&#101&#110 &#116&#104&#97&#116 c + d must equal 1. Very straightforward, yes. 296 Remember &#116&#104&#97&#116 &#97&#108&#108 &#116&#104&#101 &#114&#97&#110&#100&#111&#109 possible combinations of the members of a population would equal (c x c) + 2cd + (d &#120 &#100&#41&#44 &#111&#114 &#40&#99&#43&#100&#41 X (c+d) Then, &#99 &#43 &#100 &#61 0.4 + 0.6 &#61 &#49&#13&#10&#65&#110&#100 &#40&#99 &#120 c) &#43 &#50&#99&#100 &#43 &#40&#100 x d) = BB + Bb + bb = .24 &#43 &#46&#52&#56 &#43 &#46&#51&#48 = 1 This means that the population can &#105&#110&#99&#114&#101&#97&#115&#101 &#105&#110 &#115&#105&#122&#101&#44 &#98&#117&#116 the frequencies &#111&#102 &#66 &#97&#110&#100 &#98 will &#115&#116&#97&#121 &#116&#104&#101 &#115&#97&#109&#101&#46&#13&#10&#78&#111&#119&#44 &#115&#117&#112&#112&#111&#115&#101 we break the 4th law about not introducing another population into this one.<br> Let &#117&#115 &#115&#97&#121 &#116&#104&#97&#116 &#119&#101 add 4 more b. b + b + b &#43 &#98 &#101&#110&#116&#101&#114 &#116&#104&#101 pool. This &#98&#114&#105&#110&#103&#115 &#111&#117&#114 &#116&#111&#116&#97&#108 &#117&#112 to 34 instead of 30.<br> What will the gene and &#103&#101&#110&#111&#116&#121&#112&#105&#99 &#102&#114&#101&#113&#117&#101&#110&#99&#105&#101&#115 &#98&#101&#63&#13&#10&#102 &#40&#66&#41 = 12/34 = .35 = 35 % f &#40&#98&#41 &#61 &#50&#50&#47&#51&#52 &#61 .65 = 65% f (BB) = .12, f (Bb) = .23 and f (bb) = .42 Oppss, &#46&#52&#50 &#100&#111&#101&#115 &#110&#111&#116 &#101&#113&#117&#97&#108 1. This means that the Equilibrium law fails if the 4th law is not met. When the new genes entered the pool it resulted in a change of the population’s gene &#102&#114&#101&#113&#117&#101&#110&#99&#105&#101&#115&#46 &#72&#111&#119&#101&#118&#101&#114 &#105&#102&#13&#10&#50&#57&#55&#13&#10&#110&#111 &#111&#116&#104&#101&#114 populations where introduced then &#116&#104&#101 &#102&#114&#101&#113&#117&#101&#110&#99&#121 &#111&#102 &#46&#52&#50 would be maintained generation after &#103&#101&#110&#101&#114&#97&#116&#105&#111&#110&#46&#13&#10&#72&#111&#119&#101&#118&#101&#114 &#119&#101 &#119&#111&#117&#108&#100 &#108&#105&#107&#101 to point out that we used a very small pool in the above example.<br> If the pool &#119&#101&#114&#101 &#109&#117&#99&#104 &#108&#97&#114&#103&#101&#114 &#116&#104&#101&#110 &#116&#104&#101&#13&#10&#110&#117&#109&#98&#101&#114 of changes, even if one or two new genes jumped &#105&#110&#44 &#119&#111&#117&#108&#100 &#98&#101&#13&#10&#105&#110&#115&#105&#103&#110&#105&#102&#105&#99&#97&#110&#116&#46 &#89&#111&#117 could calculate it, but the change would be on an extremely low leve </p></p> <p> </p> </DIV> <DIV id=foot> Valid <a href="http://validator.w3.org/check?uri=referer" target="_blank">HTML 4.01</a> <a href="http://jigsaw.w3.org/css-validator/check/referer" target="_blank">CSS</a> - <a href="http://cannabica.net/order marijuana seeds.shtml" title="Order Marijuana Seeds" alt="Order Marijuana Seeds" >Order Marijuana Seeds</a>, Powered by the magic team 2/7/2012 6:28:14 PM</DIV> </DIV> <DIV class=Bottomshadow></DIV> </DIV> </body>