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This means that there can be no evolution.<br> For a &#116&#101&#115&#116 &#101&#120&#97&#109&#112&#108&#101 &#108&#101&#116 &#117&#115 consider a population whose gene pool &#99&#111&#110&#116&#97&#105&#110&#115 &#116&#104&#101 &#97&#108&#108&#101&#108&#101&#115 &#66 and b. Assign the letter c to the frequency of the dominant allele B and the letter d to the frequency of the recessive allele b.<br> In most cases you will find that c and d are actually notated as p and q by &#99&#111&#110&#118&#101&#110&#116&#105&#111&#110 &#105&#110 &#115&#99&#105&#101&#110&#99&#101&#44 &#98&#117&#116 for this example we will use c and d.] The sum of all the alleles must equal &#49&#48&#48&#37&#46&#13&#10&#83&#111 &#99 &#43 &#100 = &#49&#46&#13&#10&#65&#108&#108 &#116&#104&#101 &#114&#97&#110&#100&#111&#109 &#112&#111&#115&#115&#105&#98&#108&#101 combinations of the members of &#97&#13&#10&#112&#111&#112&#117&#108&#97&#116&#105&#111&#110 &#119&#111&#117&#108&#100 &#101&#113&#117&#97&#108 &#40&#99 x c) + 2cd &#43 &#40&#100 &#120 &#100&#41&#46 Which can also be expressed &#97&#115&#58&#13&#10&#40&#99&#43&#100&#41 &#88 &#40&#99&#43&#100&#41&#13&#10&#87&#101 &#119&#105&#108&#108 explain this in detail in moment, but it is best to know it for now. The frequencies of B and b will &#114&#101&#109&#97&#105&#110 &#117&#110&#99&#104&#97&#110&#103&#101&#100 &#103&#101&#110&#101&#114&#97&#116&#105&#111&#110 &#97&#102&#116&#101&#114&#13&#10&#103&#101&#110&#101&#114&#97&#116&#105&#111&#110 &#105&#102&#58&#13&#10&#49&#46 The &#112&#111&#112&#117&#108&#97&#116&#105&#111&#110 &#105&#115 &#108&#97&#114&#103&#101 &#101&#110&#111&#117&#103&#104&#46&#13&#10&#50&#46 There &#97&#114&#101 &#110&#111 &#109&#117&#116&#97&#116&#105&#111&#110&#115&#46&#13&#10&#50&#57&#53&#13&#10&#51&#46 &#84&#104&#101&#114&#101 are no &#112&#114&#101&#102&#101&#114&#101&#110&#99&#101&#115&#46 &#70&#111&#114 &#101&#120&#97&#109&#112&#108&#101 &#97 BB male &#100&#111&#101&#115 &#110&#111&#116 &#112&#114&#101&#102&#101&#114 &#97&#13&#10&#98&#98 female by its nature. 4. No other outside population &#101&#120&#99&#104&#97&#110&#103&#101&#115 &#103&#101&#110&#101&#115 &#119&#105&#116&#104 &#116&#104&#105&#115 model.<br> 5.<br> Natural selection must not favor any &#115&#112&#101&#99&#105&#102&#105&#99 &#105&#110&#100&#105&#118&#105&#100&#117&#97&#108&#46&#13&#10&#76&#101&#116 &#117&#115 &#105&#109&#97&#103&#105&#110&#101 a pool of genes. 12 are B &#97&#110&#100 &#49&#56 &#97&#114&#101 &#98&#46 Now remember The &#115&#117&#109 &#111&#102 &#97&#108&#108 &#116&#104&#101 alleles must equal 100%. So &#116&#104&#105&#115 &#109&#101&#97&#110&#115&#13&#10&#116&#104&#97&#116 &#116&#104&#101 &#116&#111&#116&#97&#108 in this case is 12 &#43 &#49&#56 &#61 &#51&#48&#46 So &#51&#48 &#105&#115 &#49&#48&#48&#37&#46&#13&#10&#73&#102 &#119&#101 want to find the frequencies of B and b &#97&#110&#100 &#116&#104&#101&#13&#10&#103&#101&#110&#111&#116&#121&#112&#105&#99 &#102&#114&#101&#113&#117&#101&#110&#99&#105&#101&#115 &#111&#102 &#66&#44 Bb and b then we will &#104&#97&#118&#101 &#116&#111 &#97&#112&#112&#108&#121 &#116&#104&#101&#13&#10&#115&#116&#97&#110&#100&#97&#114&#100 &#102&#111&#114&#109&#117&#108&#97 &#116&#104&#97&#116 we &#104&#97&#118&#101 &#106&#117&#115&#116 &#98&#101&#101&#110 &#115&#104&#111&#119&#110&#46&#13&#10&#102 (B) = 12/30 = 0.4 &#61 &#52&#48&#37&#13&#10&#102 &#40&#98&#41 &#61 &#49&#56&#47&#51&#48 = &#48&#46&#54 &#61 &#54&#48&#37&#13&#10&#66&#111&#116&#104 &#97&#100&#100 to make &#49&#48&#48&#37&#46 &#78&#111&#119 &#119&#101 &#107&#110&#111&#119 their &#114&#97&#116&#105&#111&#115&#46&#13&#10&#83&#111&#44&#13&#10&#99 &#43 &#100 &#61 0.4 + 0.6 &#61 &#49&#13&#10&#87&#101 &#104&#97&#118&#101 &#112&#114&#111&#118&#101&#110 that &#99 &#43 &#100 &#109&#117&#115&#116 equal 1. Very &#115&#116&#114&#97&#105&#103&#104&#116&#102&#111&#114&#119&#97&#114&#100&#44 &#121&#101&#115&#46&#13&#10&#50&#57&#54&#13&#10&#82&#101&#109&#101&#109&#98&#101&#114 &#116&#104&#97&#116 &#97&#108&#108 &#116&#104&#101 random possible combinations of the members of &#97 &#112&#111&#112&#117&#108&#97&#116&#105&#111&#110 &#119&#111&#117&#108&#100 &#101&#113&#117&#97&#108 (c x c) + 2cd + (d x d), or (c+d) X (c+d) Then, c + d = &#48&#46&#52 &#43 &#48&#46&#54 &#61 1 And (c x &#99&#41 &#43 &#50&#99&#100 &#43 (d x d) = BB + Bb + bb = .24 + .48 + .30 &#61 &#49&#13&#10&#84&#104&#105&#115 &#109&#101&#97&#110&#115 &#116&#104&#97&#116 the population can &#105&#110&#99&#114&#101&#97&#115&#101 &#105&#110 &#115&#105&#122&#101&#44 &#98&#117&#116 the frequencies of B and &#98 &#119&#105&#108&#108 &#115&#116&#97&#121 &#116&#104&#101 same. Now, suppose &#119&#101 &#98&#114&#101&#97&#107 &#116&#104&#101 &#52&#116&#104 law about not introducing another population into this one. Let us say that we add 4 more b. b + b + b + &#98 &#101&#110&#116&#101&#114 &#116&#104&#101 &#112&#111&#111&#108&#46 This &#98&#114&#105&#110&#103&#115 &#111&#117&#114 &#116&#111&#116&#97&#108 &#117&#112 &#116&#111 34 instead of 30. What will the gene &#97&#110&#100 &#103&#101&#110&#111&#116&#121&#112&#105&#99 &#102&#114&#101&#113&#117&#101&#110&#99&#105&#101&#115 &#98&#101&#63&#13&#10&#102 (B) = 12/34 = .35 = 35 % f (b) = 22/34 &#61 &#46&#54&#53 &#61 &#54&#53&#37&#13&#10&#102 (BB) = &#46&#49&#50&#44 &#102 &#40&#66&#98&#41 &#61 .23 and f (bb) = .42 Oppss, .42 does not equal &#49&#46 &#84&#104&#105&#115 &#109&#101&#97&#110&#115 &#116&#104&#97&#116 the &#69&#113&#117&#105&#108&#105&#98&#114&#105&#117&#109 &#108&#97&#119 &#102&#97&#105&#108&#115&#13&#10&#105&#102 &#116&#104&#101 4th &#108&#97&#119 &#105&#115 &#110&#111&#116 &#109&#101&#116&#46 When the new genes entered &#116&#104&#101 &#112&#111&#111&#108 &#105&#116&#13&#10&#114&#101&#115&#117&#108&#116&#101&#100 &#105&#110 a change &#111&#102 &#116&#104&#101 &#112&#111&#112&#117&#108&#97&#116&#105&#111&#110&#8217&#115 &#103&#101&#110&#101 frequencies. However if 297 no other populations where introduced &#116&#104&#101&#110 &#116&#104&#101 &#102&#114&#101&#113&#117&#101&#110&#99&#121 &#111&#102 .42 would be &#109&#97&#105&#110&#116&#97&#105&#110&#101&#100 &#103&#101&#110&#101&#114&#97&#116&#105&#111&#110 &#97&#102&#116&#101&#114 &#103&#101&#110&#101&#114&#97&#116&#105&#111&#110&#46&#13&#10&#72&#111&#119&#101&#118&#101&#114 we would like to &#112&#111&#105&#110&#116 &#111&#117&#116 &#116&#104&#97&#116 &#119&#101 used a very small pool in &#116&#104&#101 &#97&#98&#111&#118&#101 &#101&#120&#97&#109&#112&#108&#101&#46 &#73&#102 the pool were much larger then the number of changes, even if one or two new genes jumped in, &#119&#111&#117&#108&#100 &#98&#101&#13&#10&#105&#110&#115&#105&#103&#110&#105&#102&#105&#99&#97&#110&#116&#46 &#89&#111&#117 &#99&#111&#117&#108&#100 calculate it, but the change would be on an extremely &#108&#111&#119 &#108&#101&#118&#101&#119&#104&#105&#99&#104 &#116&#104&#101&#114&#101 &#105&#115 no change in the gene pool. This means that there can be &#110&#111 &#101&#118&#111&#108&#117&#116&#105&#111&#110&#46&#13&#10&#70&#111&#114 &#97 &#116&#101&#115&#116 example &#108&#101&#116 &#117&#115 &#99&#111&#110&#115&#105&#100&#101&#114 &#97 population whose &#103&#101&#110&#101&#13&#10&#112&#111&#111&#108 &#99&#111&#110&#116&#97&#105&#110&#115 &#116&#104&#101 &#97&#108&#108&#101&#108&#101&#115 B and b. Assign the letter c to &#116&#104&#101 &#102&#114&#101&#113&#117&#101&#110&#99&#121&#13&#10&#111&#102 &#116&#104&#101 &#100&#111&#109&#105&#110&#97&#110&#116 allele B &#97&#110&#100 &#116&#104&#101 &#108&#101&#116&#116&#101&#114 &#100 to the frequency of &#116&#104&#101&#13&#10&#114&#101&#99&#101&#115&#115&#105&#118&#101 &#97&#108&#108&#101&#108&#101 &#98&#46&#13&#10&#73&#110 &#109&#111&#115&#116 cases &#121&#111&#117 &#119&#105&#108&#108 &#102&#105&#110&#100 &#116&#104&#97&#116 &#99 and d are actually notated as p and q by convention in science, but &#102&#111&#114 &#116&#104&#105&#115 &#101&#120&#97&#109&#112&#108&#101 &#119&#101 &#119&#105&#108&#108 use c and &#100&#46&#93&#13&#10&#84&#104&#101 &#115&#117&#109 &#111&#102 &#97&#108&#108 the alleles must equal &#49&#48&#48&#37&#46&#13&#10&#83&#111 &#99 &#43 &#100 = 1. All the random &#112&#111&#115&#115&#105&#98&#108&#101 &#99&#111&#109&#98&#105&#110&#97&#116&#105&#111&#110&#115 &#111&#102 &#116&#104&#101 members of a population would equal (c &#120 &#99&#41 &#43 &#50&#99&#100 + (d x d). Which can also be expressed as: (c+d) &#88 &#40&#99&#43&#100&#41&#13&#10&#87&#101 &#119&#105&#108&#108 &#101&#120&#112&#108&#97&#105&#110 this in detail in moment, but it is best to know &#105&#116 &#102&#111&#114&#13&#10&#110&#111&#119&#46&#13&#10&#84&#104&#101 &#102&#114&#101&#113&#117&#101&#110&#99&#105&#101&#115 &#111&#102 B and b will remain &#117&#110&#99&#104&#97&#110&#103&#101&#100 &#103&#101&#110&#101&#114&#97&#116&#105&#111&#110 &#97&#102&#116&#101&#114&#13&#10&#103&#101&#110&#101&#114&#97&#116&#105&#111&#110 &#105&#102&#58&#13&#10&#49&#46 The population is large enough. 2. There &#97&#114&#101 &#110&#111 &#109&#117&#116&#97&#116&#105&#111&#110&#115&#46&#13&#10&#50&#57&#53&#13&#10&#51&#46 &#84&#104&#101&#114&#101 &#97&#114&#101 no preferences.<br> For example a BB male &#100&#111&#101&#115 &#110&#111&#116 &#112&#114&#101&#102&#101&#114 &#97&#13&#10&#98&#98 &#102&#101&#109&#97&#108&#101 by its nature. 4. No other outside population exchanges genes &#119&#105&#116&#104 &#116&#104&#105&#115 &#109&#111&#100&#101&#108&#46&#13&#10&#53&#46 &#78&#97&#116&#117&#114&#97&#108 selection must not &#102&#97&#118&#111&#114 &#97&#110&#121 &#115&#112&#101&#99&#105&#102&#105&#99 &#105&#110&#100&#105&#118&#105&#100&#117&#97&#108&#46&#13&#10&#76&#101&#116 us imagine a pool of genes.<br> 12 are B and 18 &#97&#114&#101 &#98&#46 &#78&#111&#119&#13&#10&#114&#101&#109&#101&#109&#98&#101&#114 &#84&#104&#101 sum &#111&#102 &#97&#108&#108 &#116&#104&#101 &#97&#108&#108&#101&#108&#101&#115 must equal 100%. So this means that &#116&#104&#101 &#116&#111&#116&#97&#108 &#105&#110 &#116&#104&#105&#115 case &#105&#115 &#49&#50 &#43 &#49&#56 = 30. So 30 is 100%. If we want to find the frequencies &#111&#102 &#66 &#97&#110&#100 &#98 &#97&#110&#100 the genotypic frequencies of &#66&#44 &#66&#98 &#97&#110&#100 &#98 then we will have to apply &#116&#104&#101&#13&#10&#115&#116&#97&#110&#100&#97&#114&#100 &#102&#111&#114&#109&#117&#108&#97 &#116&#104&#97&#116 &#119&#101 &#104&#97&#118&#101 just been shown. f (B) = &#49&#50&#47&#51&#48 &#61 &#48&#46&#52 &#61 40% f (b) &#61 &#49&#56&#47&#51&#48 &#61 &#48&#46&#54 = 60% Both &#97&#100&#100 &#116&#111 &#109&#97&#107&#101 &#49&#48&#48&#37&#46 Now we know &#116&#104&#101&#105&#114 &#114&#97&#116&#105&#111&#115&#46&#13&#10&#83&#111&#44&#13&#10&#99 &#43 &#100 = 0.4 + 0.6 = 1 We have proven that c + d must equal 1. Very straightforward, yes. 296 Remember that &#97&#108&#108 &#116&#104&#101 &#114&#97&#110&#100&#111&#109 &#112&#111&#115&#115&#105&#98&#108&#101 combinations of &#116&#104&#101 &#109&#101&#109&#98&#101&#114&#115&#13&#10&#111&#102 &#97 &#112&#111&#112&#117&#108&#97&#116&#105&#111&#110 &#119&#111&#117&#108&#100 &#101&#113&#117&#97&#108 (c x c) + 2cd + (d x d), &#111&#114 &#40&#99&#43&#100&#41 &#88 &#40&#99&#43&#100&#41&#13&#10&#84&#104&#101&#110&#44 &#99 + d &#61 &#48&#46&#52 &#43 &#48&#46&#54 = 1 And &#40&#99 &#120 &#99&#41 &#43 2cd + (d x &#100&#41&#13&#10&#61 &#66&#66 &#43 &#66&#98 + bb = .24 + .48 + .30 = &#49&#13&#10&#84&#104&#105&#115 &#109&#101&#97&#110&#115 &#116&#104&#97&#116 &#116&#104&#101 population can increase in size, but the frequencies of B &#97&#110&#100 &#98 &#119&#105&#108&#108 &#115&#116&#97&#121 the same.<br> Now, suppose we break the 4th &#108&#97&#119 &#97&#98&#111&#117&#116 &#110&#111&#116 &#105&#110&#116&#114&#111&#100&#117&#99&#105&#110&#103 another population into this one. Let &#117&#115 &#115&#97&#121 &#116&#104&#97&#116 &#119&#101 add 4 more b. b + b + b &#43 &#98 &#101&#110&#116&#101&#114 &#116&#104&#101 pool. This brings our total up to 34 &#105&#110&#115&#116&#101&#97&#100 &#111&#102&#13&#10&#51&#48&#46 &#87&#104&#97&#116 &#119&#105&#108&#108 the &#103&#101&#110&#101 &#97&#110&#100 &#103&#101&#110&#111&#116&#121&#112&#105&#99 &#102&#114&#101&#113&#117&#101&#110&#99&#105&#101&#115 be? f (B) = 12/34 = .35 = 35 % f (b) = 22/34 = .65 = 65% f (BB) = &#46&#49&#50&#44 &#102 &#40&#66&#98&#41 &#61 .23 &#97&#110&#100 &#102 &#40&#98&#98&#41 &#61 .42 Oppss, .42 does not equal 1. This means that the Equilibrium law fails if the &#52&#116&#104 &#108&#97&#119 &#105&#115 &#110&#111&#116 met. <a href="http://cannabica.net/trippystix.shtml" title="Trippystix" alt="Trippystix" >Trippystix</a> When the new genes &#101&#110&#116&#101&#114&#101&#100 &#116&#104&#101 &#112&#111&#111&#108 &#105&#116&#13&#10&#114&#101&#115&#117&#108&#116&#101&#100 in a change of &#116&#104&#101 &#112&#111&#112&#117&#108&#97&#116&#105&#111&#110&#8217&#115 &#103&#101&#110&#101 &#102&#114&#101&#113&#117&#101&#110&#99&#105&#101&#115&#46 However if 297 no other populations where introduced then &#116&#104&#101 &#102&#114&#101&#113&#117&#101&#110&#99&#121 &#111&#102 &#46&#52&#50 would be maintained generation after generation. However we &#119&#111&#117&#108&#100 &#108&#105&#107&#101 &#116&#111 &#112&#111&#105&#110&#116 out that we used a very &#115&#109&#97&#108&#108&#13&#10&#112&#111&#111&#108 &#105&#110 &#116&#104&#101 &#97&#98&#111&#118&#101 &#101&#120&#97&#109&#112&#108&#101&#46 If the pool were much larger then the number of changes, even &#105&#102 &#111&#110&#101 &#111&#114 &#116&#119&#111 new genes jumped in, would be insignificant.<br> You could calculate it, &#98&#117&#116 &#116&#104&#101 &#99&#104&#97&#110&#103&#101 &#119&#111&#117&#108&#100 be on an extremely low levewhich there is no change in the gene pool. &#84&#104&#105&#115 &#109&#101&#97&#110&#115 &#116&#104&#97&#116&#13&#10&#116&#104&#101&#114&#101 &#99&#97&#110 be no evolution. For a test example let us consider a population whose gene pool contains the &#97&#108&#108&#101&#108&#101&#115 &#66 &#97&#110&#100 &#98&#46 Assign the letter c to the frequency of &#116&#104&#101 &#100&#111&#109&#105&#110&#97&#110&#116 &#97&#108&#108&#101&#108&#101 &#66 and the letter d to the frequency of the recessive &#97&#108&#108&#101&#108&#101 &#98&#46&#13&#10&#91&#73&#110 &#109&#111&#115&#116 &#99&#97&#115&#101&#115 you will find that c and d are actually notated as p and q by convention in science, but for &#116&#104&#105&#115 &#101&#120&#97&#109&#112&#108&#101 &#119&#101 &#119&#105&#108&#108 use c and d.<br> The sum of all the alleles must equal 100%. So c + d = 1. All the random possible combinations of the members of a population would equal (c x c) + 2cd + (d x d). Which can also be expressed as: (c+d) &#88 &#40&#99&#43&#100&#41&#13&#10&#87&#101 &#119&#105&#108&#108 &#101&#120&#112&#108&#97&#105&#110 this &#105&#110 &#100&#101&#116&#97&#105&#108 &#105&#110 &#109&#111&#109&#101&#110&#116&#44 but it is best &#116&#111 &#107&#110&#111&#119 &#105&#116 &#102&#111&#114&#13&#10&#110&#111&#119&#46&#13&#10&#84&#104&#101 frequencies &#111&#102 &#66 &#97&#110&#100 &#98 &#119&#105&#108&#108 remain unchanged generation after generation &#105&#102&#58&#13&#10&#49&#46 &#84&#104&#101 &#112&#111&#112&#117&#108&#97&#116&#105&#111&#110 &#105&#115 large enough. 2. There are no mutations. 295 3. There are no preferences. For example a BB &#109&#97&#108&#101 &#100&#111&#101&#115 &#110&#111&#116 &#112&#114&#101&#102&#101&#114 a bb female by its nature. 4. No other outside population exchanges genes with this model.<br> 5.<br> Natural selection &#109&#117&#115&#116 &#110&#111&#116 &#102&#97&#118&#111&#114 &#97&#110&#121 &#115&#112&#101&#99&#105&#102&#105&#99 individual.<br> Let us imagine a pool of genes.<br> 12 are B and 18 are b. &#78&#111&#119&#13&#10&#114&#101&#109&#101&#109&#98&#101&#114 &#84&#104&#101 &#115&#117&#109 &#111&#102 all &#116&#104&#101 &#97&#108&#108&#101&#108&#101&#115 where to buy a trippy stick &#109&#117&#115&#116 &#101&#113&#117&#97&#108 100%. &#83&#111 &#116&#104&#105&#115 &#109&#101&#97&#110&#115&#13&#10&#116&#104&#97&#116 &#116&#104&#101 &#116&#111&#116&#97&#108 in &#116&#104&#105&#115 &#99&#97&#115&#101 &#105&#115 &#49&#50 &#43 18 = &#51&#48&#46 &#83&#111 &#51&#48 &#105&#115 &#49&#48&#48&#37&#46&#13&#10&#73&#102 we want &#116&#111 &#102&#105&#110&#100 &#116&#104&#101 &#102&#114&#101&#113&#117&#101&#110&#99&#105&#101&#115 of B and b and the genotypic frequencies of B, &#66&#98 &#97&#110&#100 &#98 &#116&#104&#101&#110 we will have to &#97&#112&#112&#108&#121 &#116&#104&#101&#13&#10&#115&#116&#97&#110&#100&#97&#114&#100 &#102&#111&#114&#109&#117&#108&#97 &#116&#104&#97&#116 we have just been shown. f (B) = 12/30 = 0.4 &#61 &#52&#48&#37&#13&#10&#102 &#40&#98&#41 &#61 18/30 = 0.6 = 60% Both add &#116&#111 &#109&#97&#107&#101 &#49&#48&#48&#37&#46 &#78&#111&#119 we know their ratios. So, c + d = 0.4 &#43 &#48&#46&#54 &#61 &#49&#13&#10&#87&#101 have proven that c + d must equal &#49&#46&#13&#10&#86&#101&#114&#121 &#115&#116&#114&#97&#105&#103&#104&#116&#102&#111&#114&#119&#97&#114&#100&#44 &#121&#101&#115&#46&#13&#10&#50&#57&#54&#13&#10&#82&#101&#109&#101&#109&#98&#101&#114 &#116&#104&#97&#116 all &#116&#104&#101 &#114&#97&#110&#100&#111&#109 &#112&#111&#115&#115&#105&#98&#108&#101 &#99&#111&#109&#98&#105&#110&#97&#116&#105&#111&#110&#115 &#111&#102 the members of a population would equal (c x &#99&#41 &#43 &#50&#99&#100 &#43 (d x d), or (c+d) X &#40&#99&#43&#100&#41&#13&#10&#84&#104&#101&#110&#44 &#99 &#43 &#100 = 0.4 + 0.6 = 1 And (c x c) + 2cd + <i> ivapor stick</i> &#40&#100 &#120 &#100&#41&#13&#10&#61 &#66&#66 + &#66&#98 &#43 &#98&#98&#13&#10&#61 &#46&#50&#52 + .48 + .30 &#61 &#49&#13&#10&#84&#104&#105&#115 &#109&#101&#97&#110&#115 &#116&#104&#97&#116 the population can &#105&#110&#99&#114&#101&#97&#115&#101 &#105&#110 &#115&#105&#122&#101&#44 &#98&#117&#116 the frequencies of B and b will &#115&#116&#97&#121 &#116&#104&#101 &#115&#97&#109&#101&#46&#13&#10&#78&#111&#119&#44 &#115&#117&#112&#112&#111&#115&#101 we break the 4th law about not introducing another population into this one.<br> Let us say &#116&#104&#97&#116 &#119&#101 &#97&#100&#100 &#52 more b. b + b + b + b &#101&#110&#116&#101&#114 &#116&#104&#101 &#112&#111&#111&#108&#46 &#84&#104&#105&#115 brings &#111&#117&#114 &#116&#111&#116&#97&#108 &#117&#112 &#116&#111 34 instead of 30. What will the gene and &#103&#101&#110&#111&#116&#121&#112&#105&#99 &#102&#114&#101&#113&#117&#101&#110&#99&#105&#101&#115 &#98&#101&#63&#13&#10&#102 &#40&#66&#41 = 12/34 = .35 = 35 &#37&#13&#10&#102 &#40&#98&#41 &#61 &#50&#50&#47&#51&#52 = .65 = 65% f (BB) = .12, &#102 &#40&#66&#98&#41 &#61 &#46&#50&#51 &#97&#110&#100 f (bb) &#61 &#46&#52&#50&#13&#10&#79&#112&#112&#115&#115&#44 &#46&#52&#50 &#100&#111&#101&#115 not equal 1. This means that the Equilibrium law fails if the 4th law is &#110&#111&#116 &#109&#101&#116&#46 &#87&#104&#101&#110 &#116&#104&#101 new genes entered the pool &#105&#116&#13&#10&#114&#101&#115&#117&#108&#116&#101&#100 &#105&#110 &#97 &#99&#104&#97&#110&#103&#101 of &#116&#104&#101 &#112&#111&#112&#117&#108&#97&#116&#105&#111&#110&#8217&#115 &#103&#101&#110&#101 &#102&#114&#101&#113&#117&#101&#110&#99&#105&#101&#115&#46 However if 297 no other populations where introduced &#116&#104&#101&#110 &#116&#104&#101 &#102&#114&#101&#113&#117&#101&#110&#99&#121 &#111&#102 .42 would be &#109&#97&#105&#110&#116&#97&#105&#110&#101&#100 &#103&#101&#110&#101&#114&#97&#116&#105&#111&#110 &#97&#102&#116&#101&#114 &#103&#101&#110&#101&#114&#97&#116&#105&#111&#110&#46&#13&#10&#72&#111&#119&#101&#118&#101&#114 we would like to &#112&#111&#105&#110&#116 &#111&#117&#116 &#116&#104&#97&#116 &#119&#101 used a &#118&#101&#114&#121 &#115&#109&#97&#108&#108&#13&#10&#112&#111&#111&#108 &#105&#110 &#116&#104&#101 above example. If the pool were &#109&#117&#99&#104 &#108&#97&#114&#103&#101&#114 &#116&#104&#101&#110 &#116&#104&#101&#13&#10&#110&#117&#109&#98&#101&#114 of changes, even if &#111&#110&#101 &#111&#114 &#116&#119&#111 &#110&#101&#119 genes jumped in, would be insignificant. You could calculate it, but the change would be on an extremely &#108&#111&#119 &#108&#101&#118&#101&#119&#104&#105&#99&#104 &#116&#104&#101&#114&#101 &#105&#115 &#110&#111 change in the gene pool. This means that there can be &#110&#111 &#101&#118&#111&#108&#117&#116&#105&#111&#110&#46&#13&#10&#70&#111&#114 &#97 &#116&#101&#115&#116 example let us consider a population whose gene pool contains &#116&#104&#101 &#97&#108&#108&#101&#108&#101&#115 &#66 &#97&#110&#100 b. Assign &#116&#104&#101 &#108&#101&#116&#116&#101&#114 &#99 &#116&#111 &#116&#104&#101 frequency of the dominant &#97&#108&#108&#101&#108&#101 &#66 &#97&#110&#100 &#116&#104&#101 letter d to the &#102&#114&#101&#113&#117&#101&#110&#99&#121 &#111&#102 &#116&#104&#101&#13&#10&#114&#101&#99&#101&#115&#115&#105&#118&#101 &#97&#108&#108&#101&#108&#101 &#98&#46&#13&#10&#73&#110 most cases you will find &#116&#104&#97&#116 &#99 &#97&#110&#100 &#100 are actually notated as p &#97&#110&#100 &#113 &#98&#121 &#99&#111&#110&#118&#101&#110&#116&#105&#111&#110 &#105&#110 science, but for this example we will use &#99&#13&#10&#97&#110&#100 &#100&#46&#13&#10&#84&#104&#101 &#115&#117&#109 &#111&#102 all &#116&#104&#101 &#97&#108&#108&#101&#108&#101&#115 &#109&#117&#115&#116 &#101&#113&#117&#97&#108 100%. So c + d = 1. All the random possible &#99&#111&#109&#98&#105&#110&#97&#116&#105&#111&#110&#115 &#111&#102 &#116&#104&#101 &#109&#101&#109&#98&#101&#114&#115 where to buy a trippy stick of a population would equal (c &#120 &#99&#41 &#43 &#50&#99&#100 + (d x d). Which can also be expressed as: (c+d) &#88 &#40&#99&#43&#100&#41&#13&#10&#87&#101 &#119&#105&#108&#108 &#101&#120&#112&#108&#97&#105&#110 this in detail in moment, but &#105&#116 &#105&#115 &#98&#101&#115&#116 &#116&#111 know it for now. The frequencies of &#66 &#97&#110&#100 &#98 &#119&#105&#108&#108 &#114&#101&#109&#97&#105&#110 unchanged generation after generation if: 1. The population is &#108&#97&#114&#103&#101 &#101&#110&#111&#117&#103&#104&#46&#13&#10&#50&#46 &#84&#104&#101&#114&#101 &#97&#114&#101 no mutations. 295 3. There are no preferences. For &#101&#120&#97&#109&#112&#108&#101 &#97 &#66&#66 &#109&#97&#108&#101 does &#110&#111&#116 &#112&#114&#101&#102&#101&#114 &#97&#13&#10&#98&#98 &#102&#101&#109&#97&#108&#101 &#98&#121 its nature.<br> 4.<br> No other outside population exchanges genes with this model. 5. &#78&#97&#116&#117&#114&#97&#108 &#115&#101&#108&#101&#99&#116&#105&#111&#110 &#109&#117&#115&#116 &#110&#111&#116 favor any &#115&#112&#101&#99&#105&#102&#105&#99 &#105&#110&#100&#105&#118&#105&#100&#117&#97&#108&#46&#13&#10&#76&#101&#116 &#117&#115 &#105&#109&#97&#103&#105&#110&#101 a pool &#111&#102 &#103&#101&#110&#101&#115&#46 &#49&#50 &#97&#114&#101 &#66 &#97&#110&#100 18 are b. Now remember The sum of all the &#97&#108&#108&#101&#108&#101&#115 &#109&#117&#115&#116 &#101&#113&#117&#97&#108 &#49&#48&#48&#37&#46 So &#116&#104&#105&#115 &#109&#101&#97&#110&#115&#13&#10&#116&#104&#97&#116 &#116&#104&#101 &#116&#111&#116&#97&#108 &#105&#110 this &#99&#97&#115&#101 &#105&#115 &#49&#50 &#43 &#49&#56 = 30. So 30 is 100%.<br> If we want to find the &#102&#114&#101&#113&#117&#101&#110&#99&#105&#101&#115 &#111&#102 &#66 &#97&#110&#100 b and the genotypic &#102&#114&#101&#113&#117&#101&#110&#99&#105&#101&#115 &#111&#102 &#66&#44 &#66&#98 and b then &#119&#101 &#119&#105&#108&#108 &#104&#97&#118&#101 &#116&#111 apply the standard formula that we have just been &#115&#104&#111&#119&#110&#46&#13&#10&#102 &#40&#66&#41 &#61 &#49&#50&#47&#51&#48 = 0.4 = 40% f &#40&#98&#41 &#61 &#49&#56&#47&#51&#48 &#61 &#48&#46&#54 = 60% Both add to make 100%. Now we know their ratios. So, c &#43 &#100 &#61 &#48&#46&#52 + 0.6 = 1 We have proven that c + d must equal &#49&#46&#13&#10&#86&#101&#114&#121 &#115&#116&#114&#97&#105&#103&#104&#116&#102&#111&#114&#119&#97&#114&#100&#44 &#121&#101&#115&#46&#13&#10&#50&#57&#54&#13&#10&#82&#101&#109&#101&#109&#98&#101&#114 &#116&#104&#97&#116 all the &#114&#97&#110&#100&#111&#109 &#112&#111&#115&#115&#105&#98&#108&#101 &#99&#111&#109&#98&#105&#110&#97&#116&#105&#111&#110&#115 &#111&#102 the members of a population would equal (c x c) + &#50&#99&#100 &#43 &#40&#100 &#120 d), or (c+d) &#88 &#40&#99&#43&#100&#41&#13&#10&#84&#104&#101&#110&#44 &#99 &#43 d = 0.4 &#43 &#48&#46&#54 &#61 &#49&#13&#10&#65&#110&#100 (c x c) &#43 &#50&#99&#100 &#43 &#40&#100 x d) = BB + Bb + bb = .24 + .48 &#43 &#46&#51&#48 &#61 &#49&#13&#10&#84&#104&#105&#115 &#109&#101&#97&#110&#115 that the &#112&#111&#112&#117&#108&#97&#116&#105&#111&#110 &#99&#97&#110 &#105&#110&#99&#114&#101&#97&#115&#101 &#105&#110 &#115&#105&#122&#101&#44 &#98&#117&#116 the frequencies of B and b will stay the &#115&#97&#109&#101&#46&#13&#10&#78&#111&#119&#44 &#115&#117&#112&#112&#111&#115&#101 &#119&#101 &#98&#114&#101&#97&#107 the 4th law &#97&#98&#111&#117&#116 &#110&#111&#116 &#105&#110&#116&#114&#111&#100&#117&#99&#105&#110&#103 &#97&#110&#111&#116&#104&#101&#114&#13&#10&#112&#111&#112&#117&#108&#97&#116&#105&#111&#110 into this one. Let &#117&#115 &#115&#97&#121 &#116&#104&#97&#116 &#119&#101 add 4 &#109&#111&#114&#101 &#98&#46&#13&#10&#98 &#43 &#98 + b + b enter the pool. This &#98&#114&#105&#110&#103&#115 &#111&#117&#114 &#116&#111&#116&#97&#108 &#117&#112 to 34 instead of 30.<br> What will the gene and genotypic frequencies be? f (B) = 12/34 = .35 = 35 % f (b) = 22/34 = .65 = 65% f (BB) = .12, f (Bb) = &#46&#50&#51 &#97&#110&#100 &#102 &#40&#98&#98&#41 = &#46&#52&#50&#13&#10&#79&#112&#112&#115&#115&#44 &#46&#52&#50 &#100&#111&#101&#115 &#110&#111&#116 &#101&#113&#117&#97&#108 1. This means that the Equilibrium law fails if the 4th law is not met. When the new genes entered the pool it resulted in a change of the population’s gene frequencies.<br> However &#105&#102&#13&#10&#50&#57&#55&#13&#10&#110&#111 &#111&#116&#104&#101&#114 &#112&#111&#112&#117&#108&#97&#116&#105&#111&#110&#115 &#119&#104&#101&#114&#101 introduced then the frequency of &#46&#52&#50 &#119&#111&#117&#108&#100&#13&#10&#98&#101 &#109&#97&#105&#110&#116&#97&#105&#110&#101&#100 &#103&#101&#110&#101&#114&#97&#116&#105&#111&#110 after generation. However we &#119&#111&#117&#108&#100 &#108&#105&#107&#101 &#116&#111 &#112&#111&#105&#110&#116 out that we used a very small pool &#105&#110 &#116&#104&#101 &#97&#98&#111&#118&#101 &#101&#120&#97&#109&#112&#108&#101&#46 If the pool were much larger then the number of changes, even if one or two new genes &#106&#117&#109&#112&#101&#100 &#105&#110&#44 &#119&#111&#117&#108&#100 &#98&#101&#13&#10&#105&#110&#115&#105&#103&#110&#105&#102&#105&#99&#97&#110&#116&#46 You could &#99&#97&#108&#99&#117&#108&#97&#116&#101 &#105&#116&#44 &#98&#117&#116 &#116&#104&#101 change would be on an extremely low leve </div><a href="http://cannabica.net/orange bud/" title="Orange Bud" alt="Orange Bud" >Orange Bud</a></p> <h2> ivapor stick</h2> <p> Although hash from the area had been readily available in the late 70's, the Soviet invasion of that country greatly reduced exports. In 1985, an Afghan refugee told Nevil the (cannabis) fields around Mazar-i-Sharif were being destroyed. ""That was what I needed to hear"" says Nevil, "" I caught the next plane to Pakistan to save the strain""" """After being smuggled into a refugee camp in Peshawar while lying on the floor of a car, Nevil made contact with a 30-year old Muslim fanatic who had a throbbing vein that ran from between his eyes straight up to his forehead. The man took a lump of black hash out of his pocket and told Nevil that it had been processed by his uncle, a man known as Mister Hashish. Surrounded by four men pointing machine guns at him, Nevil set about negotiating with Mr. Hashish, a Mujahedin commander, and finally persuaded him to send a squad of his men 280 miles into Soviet occupied territory and come back with two kilos of healthy Mazari seeds. Nevil added "" He thought I was ridiculous because I didn't want to buy hashish or opium. Nobody had ever come out to buy seeds, and at first he had no idea what I was talking about. I tried there trying to explain genetics to this tribal hash leader in sign language. When he finally figured out what I wanted, he asked too much money. I took a zero off his price and gave him 10% up front. He called me a bandit, but I had the seeds four days later."" - Nevil Schoenbottom, High Times Magazine, March 1987" "If you got the real stuff from serious, the trick will be remaining patient while those babies mature. My AK-47 seeds produced two outstanding mothers, each of which are about the best smoke I or any of my friends have ever had (plus a few other very interesting plants). My seedlings didn't show a lot of vigor, but that may have been from overwatering on my part - I was completely new at the whole thing. They tend to be pretty sativa in appearance, though I did get a couple of slightly indica types. They show preflowers at about six weeks, and do best topped back before flowering. They grow a lot, and stretch if you're not careful with them. My best smoking mothers weren't great yielders, but they were tall. Just not great branching. Best to grow them SOG with tight spacing. Although I did get one mother that branched like crazy, but the buds were stringy and stemmy and I won't be growing her out again. I never had any problems with infestations or nutrients. You can give them high nutrient doses and they do fine. Flowering time tends to be long, between 56-70 days, depending on the mother, although you can go short, but it hurts the yield. Yields in general were not great, but then neither is my growing technique and experience. Others report pretty good yields from what I hear. The high is just plain supreme. Very up, cerebral, but smooth and completely non-paranoid. No racing. My musician friends completely love the stuff. Very compatible with a<a href="http://cannabica.net/pdf/grow-a-weed-plant.pdf">grow-a-weed-plant</a></p> <h2> where to buy a trippy stick</h2> <p><div align="left"> where can you buy trippy stick cartdridges online <u> Blue Trippy Stick</u> <u> ivapor trippy stick</u> &#73&#116 &#105&#115 &#112&#111&#115&#115&#105&#98&#108&#101&#13&#10&#116&#104&#97&#116 &#105&#116&#115 main &#97&#99&#116&#105&#118&#101 &#99&#111&#110&#115&#116&#105&#116&#117&#101&#110&#116 &#116&#44&#108&#45&#84&#72&#67 &#99&#111&#117&#108&#100 &#98&#101&#99&#111&#109&#101 a <a href="http://cannabica.net/howtomakeatrippystick.shtml" title="Howtomakeatrippystick" alt="Howtomakeatrippystick" >Howtomakeatrippystick</a> viable drug, but it is most likely that &#116&#104&#101 &#109&#97&#114&#107&#101&#116&#97&#98&#108&#101 &#112&#114&#111&#100&#117&#99&#116&#115 &#119&#105&#108&#108 &#99&#111&#109&#101 from the <a href="http://cannabica.net/howtomakeatrippystick.shtml" title="Howtomakeatrippystick" alt="Howtomakeatrippystick" >Howtomakeatrippystick</a> synthetic analogs, where the undesirable side effects and physical characteristics of t,l-THC have been modified or eliminated </div></p> <p> </p> </DIV> <DIV id=foot> Valid <a href="http://validator.w3.org/check?uri=referer" target="_blank">HTML 4.01</a> <a href="http://jigsaw.w3.org/css-validator/check/referer" target="_blank">CSS</a> - <a href="http://cannabica.net/trippystickcartridgesonline.shtml" title="Trippystickcartridgesonline" alt="Trippystickcartridgesonline" >Trippystickcartridgesonline</a>, Powered by the magic team 2/6/2012 3:50:41 PM</DIV> </DIV> <DIV class=Bottomshadow></DIV> </DIV> </body>